嗯，这是一个完整的答案如何用两个地方之间的谷歌距离矩阵api来计算距离和时间。 如果你不使用Maven，那么你必须在你的类路径设置这些罐子
的pom.xml
<!-- https://mvnrepository.com/artifact/com.squareup.okhttp3/okhttp -->
<dependency>
<groupId>com.squareup.okhttp3</groupId>
<artifactId>okhttp</artifactId>
<version>3.9.0</version>
</dependency>
<!-- https://mvnrepository.com/artifact/com.squareup.okio/okio -->
<dependency>
<groupId>com.squareup.okio</groupId>
<artifactId>okio</artifactId>
<version>1.12.0</version>
</dependency>
<!-- https://mvnrepository.com/artifact/com.googlecode.json-simple/json-simple -->
<dependency>
<groupId>com.googlecode.json-simple</groupId>
<artifactId>json-simple</artifactId>
<version>1.1.1</version>
</dependency>
<!-- https://mvnrepository.com/artifact/com.google.api-client/google-api-client -->
<dependency>
<groupId>com.google.api-client</groupId>
<artifactId>google-api-client</artifactId>
<version>1.23.0</version>
</dependency>
这是JSON格式发送HTTP请求并获得数据的类
package google.distance.api;
import java.io.IOException;
import org.springframework.stereotype.Component;
import okhttp3.OkHttpClient;
import okhttp3.Request;
import okhttp3.Response;
@Component
public class DistanceTime {
private static final String API_KEY="YOUR KEY";
OkHttpClient client = new OkHttpClient();
public String calculate(String source ,String destination) throws IOException {
String url="https://maps.googleapis.com/maps/api/distancematrix/json?origins="+source+"&destinations="+destination+"&key="+ API_KEY;
Request request = new Request.Builder()
.url(url)
.build();
Response response = client.newCall(request).execute();
return response.body().string();
}
}
由于我使用Spring，所以这里是我的控制器方法来获取数据
private DistanceTime distance;
@Autowired
public void setDistance(DistanceTime distance) {
this.distance = distance;
}
public ModelAndView Api(@RequestParam("picking_up") String source,@RequestParam("dropping_off") String destination,@RequestParam("pick_up_date") String time) {
try {
//method of DistanceTime Class
String response=distance.calculate(source,destination);
System.out.println(response);
}
catch(Exception e) {
System.out.println("Exception Occurred");
}
return new ModelAndView("home");
}
现在艰难的部分迭代JSON数据以获取距离和时间 在上述方法中，我得到了json数据的可变响应，所以这里是从中提取距离和时间的代码 响应是类似于
{
"destination_addresses" : [
"Private"
],
"origin_addresses" : [ "Private" ],
"rows" : [
{
"elements" : [
{
"distance" : {
"text" : "1,052 km",
"value" : 1051911
},
"duration" : {
"text" : "17 hours 10 mins",
"value" : 61785
},
"status" : "OK"
}
]
}
],
"status" : "OK"
}
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(response);
JSONObject jsonobj=(JSONObject)obj;
JSONArray dist=(JSONArray)jsonobj.get("rows");
JSONObject obj2 = (JSONObject)dist.get(0);
JSONArray disting=(JSONArray)obj2.get("elements");
JSONObject obj3 = (JSONObject)disting.get(0);
JSONObject obj4=(JSONObject)obj3.get("distance");
JSONObject obj5=(JSONObject)obj3.get("duration");
System.out.println(obj4.get("text"));
System.out.println(obj5.get("text"));
}
catch(Exception e) {
e.printStackTrace();
}
对于那些使用Haversine公式，距离矩阵不会返回直线（“如同乌鸦”，大圆圈）的距离。 – geocodezip
是的，谢谢我刚才意识到并编写了代码。但是，如何从这些地方驾驶距离。该API令我感到困惑 – tsaebeht
[编辑]你的问题，请澄清它。 – geocodezip