单声道嵌入：用于同步托管和本地互斥的互斥

Question

有一个加载单声道程序集的原生C++应用程序（linux）。 如何在同一应用程序的托管部分和本机部分之间共享互斥锁（或其模拟）？

是这样的：

本地部分：

native_lock_mutex(&db_mutex); 
// do something with db 
native_unlock_mutex(&db_mutex); 

单声道部分：

managed_lock_mutex(db_mutex); 
// do something with db 
managed_unlock_mutex(db_mutex); 

Answer 1

您必须公开本机互斥托管代码，像这样：

C代码：

pthread_mutex_t* managed_get_mutex() 
{ 
    return &db_mutex; 
} 

void managed_lock_mutex (pthread_mutex_t *mutex) 
{ 
    pthread_mutex_lock (mutex): 
} 

void managed_unlock_mutex (pthread_mutex_t *mutex) 
{ 
    phtread_mutex_unlock (mutex); 
} 

C＃代码：

class NativMutex { 
    [DllImport ("nativeLibrary")] 
    public static export IntPtr get_managed_mutex(); 

    [DllImport ("nativeLibrary")] 
    public static export void managed_lock_mutex (IntPtr mutex); 

    [DllImport ("nativeLibrary")] 
    public static export void managed_unlock_mutex (IntPtr mutex); 
}