2017-02-15 102 views
1

我正在构建一个应用程序,它将用户输入的开销存储到SQLite数据库中,并将它们显示在RecyclerView中。我的应用程序目前有一个带3个选项卡的视图分页器。每个选项卡切换到一个新的片段,该片段从SQLite数据库中获取来自不同时间段的费用,特别是“今日,本周”和所有显示在RecyclerView中的费用。在每个列表中,我可以长按一个项目并删除它,它将从SQLite数据库和当前的RecyclerView中删除它并更新列表。因为有可能一个列表中的项目会出现在其他列表中,所以我想实现一种方法,以便我可以检查其他两个片段中的列表,以便删除任何项目,并将其从中删除,但我有难以找出最好的方法来做到这一点。使用viewpager同时更新多个相同数据的列表

现在,我可以很容易地认为寻呼机重建每一个将再次调用数据库,并创造全新的列表片段,但这是低效的。有没有人对我如何实现这一目标有任何想法?下面是我当前的代码:

ExpensePagerAdapter

class ExpensePagerAdapter extends FragmentPagerAdapter { 
    private String[] tabTitles = {getString(R.string.label_today), 
      getString(R.string.label_week), getString(R.string.label_all)}; 


    ExpensePagerAdapter(FragmentManager fm){ 
     super(fm); 
    } 

    @Override 
    public int getCount() { 
     return tabTitles.length; 
    } 

    @Override 
    public Fragment getItem(int position) { 
     return ExpenseListFragment.newInstance(position); 
    } 

    @Override 
    public CharSequence getPageTitle(int position) { 
     return tabTitles[position]; 
    } 

} 

ExpenseListFragment

public class ExpenseListFragment extends Fragment{ 
private static final String LOG_TAG = "ExpenseListFragment"; 
private static final String ARG_TYPE = "viewType"; 
private RecyclerView rv; 
private List<Expense> dayViewExpenses; 
private List<LocalDate> weekViewDay; 
private List<List<Expense>> weekViewExpenses; 
private List<Expense> allExpenses; 

public static ExpenseListFragment newInstance(int viewType){ 
    Bundle bundle = new Bundle(); 
    bundle.putInt(ARG_TYPE, viewType); 
    ExpenseListFragment f = new ExpenseListFragment(); 
    f.setArguments(bundle); 
    return f; 
} 

@Nullable 
@Override 
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) { 
    Log.d(LOG_TAG, "onCreateView"); 
    View v = inflater.inflate(R.layout.fragment_list, container, false); 
    rv = (RecyclerView) v.findViewById(R.id.rv_list); 
    rv.setLayoutManager(new LinearLayoutManager(getActivity())); 
    int viewType = getArguments().getInt(ARG_TYPE); 
    switch(viewType) { 
     case 0: 
      setupDayView(); 
      break; 
     case 1: 
      setupWeekView(); 
      break; 
     case 2: 
      setUpAllView(); 
      break; 
     default: 
    } 
    return v; 
} 

private void setupDayView(){ 
    dayViewExpenses = new ArrayList<>(); 
    LocalDate currentDate = new LocalDate(); 
    for (Expense e : ExpenseDb.getInstance(getActivity()).getAllExpenses()) { 
     if (currentDate.getMonthOfYear() == e.getMonth() 
       && currentDate.getDayOfMonth() == e.getDay() && currentDate.getYear() == e.getYear()) { 
      dayViewExpenses.add(e); 
     } 
    } 
    rv.setAdapter(new ExpenseAdapter(getActivity(), dayViewExpenses)); 
} 

private void setupWeekView(){ 
    weekViewDay = new ArrayList<>(); 
    weekViewExpenses = new ArrayList<>(); 
    LocalDate weekStart = new LocalDate().withDayOfWeek(DateTimeConstants.MONDAY); 
    for (int i = 0; i < 7; i++) { 
     LocalDate dayOfWeek = weekStart.plusDays(i); 
     weekViewDay.add(dayOfWeek); 
     List<Expense> expensesForDay = new ArrayList<>(); 
     for (Expense expense: ExpenseDb.getInstance(getActivity()).getAllExpenses()) { 
      if (expense.getDay() == dayOfWeek.getDayOfMonth() && expense.getMonth() == dayOfWeek.getMonthOfYear() 
        && expense.getYear() == dayOfWeek.getYear()) { 
       expensesForDay.add(expense); 
      } 
     } 
     weekViewExpenses.add(expensesForDay); 
    } 
    rv.setAdapter(new WeekViewAdapter(getActivity(), weekViewDay, weekViewExpenses)); 
} 

private void setUpAllView(){ 
    allExpenses = ExpenseDb.getInstance(getActivity()).getAllExpenses(); 
    rv.setAdapter(new ExpenseAdapter(getActivity(), allExpenses)); 
} 

}

任何帮助将是巨大的,因为我一直在努力找出一种理想的方式来完成这个。

回答

1

您可以使用事件总线库(http://square.github.io/otto/)针对此问题。您不能在ExpenseListFragments上附加总线,并同时向该片段发送对象。重新创建适配器对于设备来说代价太高。

+0

感谢您的回复,我将着眼于此并更新您的行动方式。 – BroccolliBeef

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