有了我上一个问题的参考,我有一个关于添加一些条件的$ lookup的问题。您可以从以下链接描述中获得足够的有关问题的参考。
照片:
{_id: 1, photo_name: '1.jpg', photo_description: 'description 1', album_id: 1, flag:1 },
{_id: 2, photo_name: '2.jpg', photo_description: 'description 2', album_id: 1, flag:1 },
{_id: 3, photo_name: '3.jpg', photo_description: 'description 3', album_id: 1, flag:1 },
{_id: 4, photo_name: '4.jpg', photo_description: 'description 4', album_id: 2, flag:0 },
{_id: 5, photo_name: '5.jpg', photo_description: 'description 5', album_id: 2, flag:0 },
{_id: 6, photo_name: '6.jpg', photo_description: 'description 6', album_id: 2}
专辑:
{_id: 1, album_name: "my album 1", album_description: "album description 1", emoji_id: 1},
{_id: 2, album_name: "my album 2", album_description: "album description 2", emoji_id: 2},
{_id: 3, album_name: "my album 3", album_description: "album description 3", emoji_id: 3},
{_id: 4, album_name: "my album 4", album_description: "album description 4", emoji_id: 4},
{_id: 5, album_name: "my album 5", album_description: "album description 5", emoji_id: 5}
表情:
{_id: 1, emoji_name: "1.jpg"},
{_id: 2, emoji_name: "2.jpg"},
{_id: 3, emoji_name: "3.jpg"},
{_id: 4, emoji_name: "4.jpg"},
{_id: 5, emoji_name: "5.jpg"},
{_id: 6, emoji_name: "6.jpg"},
{_id: 7, emoji_name: "7.jpg"},
{_id: 8, emoji_name: "8.jpg"}
测试记录分页:
2
假设我在照片集合中添加了另一个标志字段,现在我只想计算标志为1的那些照片。
我试图在查询中的$查找后立即添加$匹配,但它失败,它不排除标志为0的照片,并且在计数器中它也不会标记条件。
本次输出 有3张照片出来的10张照片将其具有标志0。而且我们不能认为这些照片,其标志为0,所以预计总数为7张照片,但数返回10张照片,虽然我申请的条件国旗在照片中。
当前查询:
db
.album
.aggregate([
{
$lookup:{
from:"photo",
localField:"_id",
foreignField:"album_id",
as:"photo"
}
},
{
$match:{
"photo.flag": 1
}
},
{
$lookup:{
from:"emoji",
localField:"album_emoji",
foreignField:"_id",
as:"emoji"
}
},
{
$project:{
album_name:"$album_name",
album_description:"$album_description",
album_emoji:"$emoji.image_name",
photo:"$photo",
total_photos: {$size: "$photo"}
}
}
])
.toArray();
预期输出:
[
{
"_id" : 1,
"album_name" : "Album 1",
"album_description" : "Album description 1",
"album_emoji" : [
"1.jpg"
],
"total_photos" : 3,
"photo" : [
{
"_id" : 1,
"album_id" : 1,
"photo_description" : "description 1",
"photo_name" : "1.jpg",
"flag" : 0,
},
{
"_id" : 2,
"album_id" : 1,
"photo_description" : "description 2",
"photo_name" : "2.jpg",
"flag" : 0,
},
{
"_id" : 1,
"album_id" : 1,
"photo_description" : "description 3",
"photo_name" : "3.jpg",
"flag" : 0,
}
]
}
]
当前输出:
[
{
"_id" : 1,
"album_name" : "Album 1",
"album_description" : "Album description 1",
"album_emoji" : [
"1.jpg"
],
"total_photos" : 5,
"photo" : [
{
"_id" : 1,
"album_id" : 1,
"photo_description" : "description 1",
"photo_name" : "1.jpg",
"flag" : 1,
},
{
"_id" : 2,
"album_id" : 1,
"photo_description" : "description 2",
"photo_name" : "2.jpg",
"flag" : 1,
},
{
"_id" : 3,
"album_id" : 1,
"photo_description" : "description 3",
"photo_name" : "3.jpg",
"flag" : 1,
},
{
"_id" : 4,
"album_id" : 1,
"photo_description" : "description 4",
"photo_name" : "4.jpg",
"flag" : 0,
},
{
"_id" : 5,
"album_id" : 1,
"photo_description" : "description 5",
"photo_name" : "5.jpg",
"flag" : 0,
}
]
}
]
它确实排除了“photo.flag”为0的照片。你在使用MongoDB 3.2吗? – notionquest
是的,我正在使用mongoDB 3.2 –
@notionquest:是的我使用MongoDB3.2,也是这个查询工作我..但对我来说,它不排除recods,并没有给出总的照片计数器的正确结果。 –