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执行以下python脚本后,我收到BadStatusLine。我如何打印有关BadStatusLine的详细信息?python:打印有关BadStatusLine错误的信息
#!/usr/bin/python
import urllib
import urllib2
import httplib
try:
# NoActiveDevsPerQtr
request = urllib2.Request('http://127.0.0.1:8090')
request.add_header('Accept', 'text/csv')
request.add_header('User-Agent', 'python-script')
request.add_data("""
<? xml version="1.0"?>
<log_query>
<querytype>ListPerQtr</querytype>
<year>2014</year>
<quarter>3</quarter>
</log_query>
""")
response = urllib2.urlopen(request)
content = response.read()
print content
except httplib.BadStatusLine as e:
print e
打印e不打印任何东西。
Traceback (most recent call last):
File "./IQueryTests.py", line 25, in <module>
response = urllib2.urlopen(request)
File "/usr/lib64/python2.6/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib64/python2.6/urllib2.py", line 391, in open
response = self._open(req, data)
File "/usr/lib64/python2.6/urllib2.py", line 409, in _open
'_open', req)
File "/usr/lib64/python2.6/urllib2.py", line 369, in _call_chain
result = func(*args)
File "/usr/lib64/python2.6/urllib2.py", line 1190, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib64/python2.6/urllib2.py", line 1163, in do_open
r = h.getresponse()
File "/usr/lib64/python2.6/httplib.py", line 990, in getresponse
response.begin()
File "/usr/lib64/python2.6/httplib.py", line 391, in begin
version, status, reason = self._read_status()
File "/usr/lib64/python2.6/httplib.py", line 355, in _read_status
raise BadStatusLine(line)
httplib.BadStatusLine
您能否显示正在抛出的实际错误? – 2014-10-30 15:10:18
可能[dupe](http://stackoverflow.com/questions/1767934/why-am-i-getting-this-error-in-python-httplib)? – Noelkd 2014-10-30 15:34:32