嗨我有一个名为image.txt的文件,其中包含大约5,00,000图像url.I想读取url并下载图像并将其保存在一个目录中。如果图像不可下载I想要打印异常并重新开始下载其他文件,我可以通过优化的方式来实现。python中的图像下载
import sys
import os
import urllib
def isValidFile(path):
if not os.path.isfile(path):
print "Path " + path + " doesn't exist! Aborting..."
exit(1)
def isValidDir(path):
if not os.path.isdir(path):
print "Path " + path + " doesn't exist! Aborting..."
exit(1)
def normalize(url):
url = url.split("/")[-1]
return url.split("\n")[0]
# Execution Starts Here
urls = sys.argv[1]
isValidFile(urls)
out_dir = sys.argv[2]
isValidDir(out_dir)
with open(urls) as url_array:
for url in url_array:
urllib.urlretrieve(url, os.path.join(out_dir, normalize(url)))
print("Images Downloaded")
什么是与你的现有代码的问题?你有错误吗? –
我非常困惑你的代码,以及你正在尝试做什么。你可以放置它并正确缩进(缩进不正确,尤其是在后半部分) – Zizouz212