我正在使用Set,但现在由于小部件限制,我需要使用list.a 我的映射文件使用SET和List的示例如下。有人可以帮我放置列表索引。我有些困惑。使用列表在休眠状态下使用列表时配置列表索引
**Attribute Mapping File using Set**
?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 5:25:09 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Attribute" table="ATTRIBUTE">
<id name="AttributeId" type="long">
<column name="ATTRIBUTEID" />
<generator class="native" />
</id>
<property name="AttributeName" type="java.lang.String">
<column name="ATTRIBUTENAME" />
</property>
<set name="Options" table="ATTRIBUTEOPTION" inverse="false" cascade="all" lazy="true">
<key>
<column name="ATTRIBUTEID" />
</key>
<one-to-many class="h.AttributeOption" />
</set>
</class>
</hibernate-mapping>
**Category Mapping File using Set**
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 8:37:02 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Category" table="CATEGORY">
<id name="CategoryId" type="long">
<column name="CATEGORYID" />
<generator class="native" />
</id>
<property name="CategoryName" type="java.lang.String">
<column name="CATEGORYNAME" />
</property>
<many-to-one name="ParentCategory" class="h.Category">
<column name="PARENT_CATEGORY_ID" />
</many-to-one>
<set name="SubCategory" lazy="true" cascade="all-delete-orphan" inverse="true">
<key>
<column name="PARENT_CATEGORY_ID" />
</key>
<one-to-many class="h.Category" />
</set>
<set name="AllAttributes" table="ATTRIBUTE" inverse="false" lazy="true" cascade="all">
<key>
<column name="CATEGORYID" />
</key>
<one-to-many class="h.Attribute" />
</set>
</class>
</hibernate-mapping>
分类映射文件,而不列表索引
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Category" table="CATEGORY">
<id name="CategoryId" type="long">
<column name="CATEGORYID" />
<generator class="assigned" />
</id>
<property name="CategoryName" type="java.lang.String">
<column name="CATEGORYNAME" />
</property>
<many-to-one name="ParentCategory" class="h.Category" fetch="join">
<column name="PARENTCATEGORY" />
</many-to-one>
<list name="SubCategory" inverse="false" table="CATEGORY" lazy="true">
<key>
<column name="CATEGORYID" />
</key>
<list-index></list-index>
<one-to-many class="h.Category" />
</list>
<list name="AllAttributes" inverse="false" table="ATTRIBUTE" lazy="true" cascade="all">
<key>
<column name="CATEGORYID" />
</key>
<list-index></list-index>
<one-to-many class="h.Attribute" />
</list>
</class>
</hibernate-mapping>
使用清单,就不一一列举指数
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Attribute" table="ATTRIBUTE">
<id name="AttributeId" type="long">
<column name="ATTRIBUTEID" />
<generator class="assigned" />
</id>
<property name="AttributeName" type="java.lang.String">
<column name="ATTRIBUTENAME" />
</property>
<list name="Options" inverse="false" table="ATTRIBUTEOPTION" lazy="true" cascade="all">
<key>
<column name="ATTRIBUTEID" />
</key>
<list-index></list-index>
<one-to-many class="h.AttributeOption" />
</list>
</class>
</hibernate-mapping>
还有一两件事,我没有使用任何索引! – Noor 2010-12-17 10:28:33
您已发布3个关于此映射的问题,请问您的答案是否有帮助? – Ralph 2010-12-17 12:29:35
不幸的是 – Noor 2010-12-17 16:08:11