Linux的从头开始有这个function in /etc/profile
# Functions to help us manage paths. Second argument is the name of the
# path variable to be modified (default: PATH)
pathremove() {
local IFS=':'
local NEWPATH
local DIR
local PATHVARIABLE=${2:-PATH}
for DIR in ${!PATHVARIABLE} ; do
if [ "$DIR" != "$1" ] ; then
NEWPATH=${NEWPATH:+$NEWPATH:}$DIR
fi
done
export $PATHVARIABLE="$NEWPATH"
}
这是为了与这些功能用于添加到路径,让你不这样做冗余:
pathprepend() {
pathremove $1 $2
local PATHVARIABLE=${2:-PATH}
export $PATHVARIABLE="$1${!PATHVARIABLE:+:${!PATHVARIABLE}}"
}
pathappend() {
pathremove $1 $2
local PATHVARIABLE=${2:-PATH}
export $PATHVARIABLE="${!PATHVARIABLE:+${!PATHVARIABLE}:}$1"
}
简单用法是给pathremove
删除目录路径 - 但请记住它必须完全匹配:
$ pathremove /home/username/anaconda3/bin
这将从您的路径中删除该目录的每个实例。
如果您想要路径中的目录,但没有冗余,您可以使用其他功能之一,例如, - 为您的具体情况:
$ pathprepend /usr/local/sbin
$ pathappend /usr/local/bin
$ pathappend /usr/sbin
$ pathappend /usr/bin
$ pathappend /sbin
$ pathappend /bin
$ pathappend /usr/games
但是,除非可读性的关注,在这一点上,你最好只是在做:
$ export PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games
哪儿去定义它的6倍?在哪些文件? – hovanessyan 2012-07-25 14:06:12
可能重复[在Bash中从$ PATH变量中删除路径的最优雅方式是什么?](http://stackoverflow.com/questions/370047/what-is-the-most-elegant-way-to -remove-a-path-from-the-path-variable-in-bash) – 2014-10-17 12:30:32