查询生成器或调用本身有什么问题？

Question

我有一个存储库这样的功能：

public function buscarConstanciaProducto($solicitudUsuario, $productoSolicitud) 
{ 
    $builder = $this->getEntityManager()->createQueryBuilder(); 
    $builder->select(array('su', 'p', 'ps', 'c')) 
      ->from('AppBundle:SolicitudUsuario', 'su') 
      ->leftJoin('su.producto_solicitud', 'ps') 
      ->leftJoin('ps.producto', 'p') 
      ->leftJoin('su.constancias', 'c') 
      ->where('su.id = ?', $solicitudUsuario) 
      ->andWhere('ps.id = ?', $productoSolicitud); 

    return $builder->getResult(); 
} 

我想从我的控制器调用它如下：

$result = $em->getRepository("AppBundle:Constancia")->buscarConstanciaProducto(
    (int) $request->query->get('id'), // this gets 18 
    $productoSolicitud->getId() // this gets 25 
); 

但我得到这个错误：

Warning: get_class() expects parameter 1 to be object, integer given

那里有什么问题？

这是一个完整的堆栈跟踪：

[1] Symfony\Component\Debug\Exception\ContextErrorException: Warning: get_class() expects parameter 1 to be object, integer given 
    at n/a 
     in /var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base.php line 92 

    at Symfony\Component\Debug\ErrorHandler->handleError('2', 'get_class() expects parameter 1 to be object, integer given', '/var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base.php', '92', array('arg' => '18', 'this' => object(Andx))) 
     in line 

    at get_class('18') 
     in /var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base.php line 92 

    at Doctrine\ORM\Query\Expr\Base->add('18') 
     in /var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base.php line 74 

    at Doctrine\ORM\Query\Expr\Base->addMultiple(array('su.id = ?', '18')) 
     in /var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base.php line 63 

    at Doctrine\ORM\Query\Expr\Base->__construct(array('su.id = ?', '18')) 
     in /var/www/html/project.dev/vendor/doctrine/orm/lib/Doctrine/ORM/QueryBuilder.php line 871 

    at Doctrine\ORM\QueryBuilder->where('su.id = ?', '18') 
     in /var/www/html/project.dev/src/Sencamer/AppBundle/Entity/Repository/ConstanciaRepository.php line 23 

    at AppBundle\Entity\Repository\ConstanciaRepository->buscarConstanciaProducto('18', '25') 
     in /var/www/html/project.dev/src/Sencamer/AppBundle/Controller/Comunes/ListadoController.php line 96 

    at AppBundle\Controller\Comunes\ListadoController->getConstanciaProductosSolicitudAction(object(Request)) 
     in line 

    at ReflectionMethod->invokeArgs(object(ListadoController), array(object(Request))) 
     in /var/www/html/project.dev/vendor/jms/cg/src/CG/Proxy/MethodInvocation.php line 63 

    at CG\Proxy\MethodInvocation->proceed() 
     in /var/www/html/project.dev/vendor/jms/security-extra-bundle/JMS/SecurityExtraBundle/Security/Authorization/Interception/MethodSecurityInterceptor.php line 120 

    at JMS\SecurityExtraBundle\Security\Authorization\Interception\MethodSecurityInterceptor->intercept(object(MethodInvocation)) 
     in /var/www/html/project.dev/vendor/jms/cg/src/CG/Proxy/MethodInvocation.php line 58 

    at CG\Proxy\MethodInvocation->proceed() 
     in /var/www/html/project.dev/app/cache/dev/jms_diextra/proxies/Sencamer-AppBundle-Controller-Comunes-ListadoController.php line 30 

    at EnhancedProxy72c8de70_7ca524686d92d76741252b9b0630ee44b00c6576\__CG__\AppBundle\Controller\Comunes\ListadoController->getConstanciaProductosSolicitudAction(object(Request)) 
     in line 

    at call_user_func_array(array(object(ListadoController), 'getConstanciaProductosSolicitudAction'), array(object(Request))) 
     in /var/www/html/project.dev/app/bootstrap.php.cache line 3022 

    at Symfony\Component\HttpKernel\HttpKernel->handleRaw(object(Request), '1') 
     in /var/www/html/project.dev/app/bootstrap.php.cache line 2984 

    at Symfony\Component\HttpKernel\HttpKernel->handle(object(Request), '1', true) 
     in /var/www/html/project.dev/app/bootstrap.php.cache line 3133 

    at Symfony\Component\HttpKernel\DependencyInjection\ContainerAwareHttpKernel->handle(object(Request), '1', true) 
     in /var/www/html/project.dev/app/bootstrap.php.cache line 2377 

    at Symfony\Component\HttpKernel\Kernel->handle(object(Request)) 
     in /var/www/html/project.dev/web/app_dev.php line 20 

Answer 1

您的问题似乎是：where()，使用这种方式，希望类似的额外表达。

/** 
* Specifies one or more restrictions to the query result. 
* Replaces any previously specified restrictions, if any. 
* 
* <code> 
*  $qb = $em->createQueryBuilder() 
*   ->select('u') 
*   ->from('User', 'u') 
*   ->where('u.id = ?'); 
* 
*  // You can optionally programatically build and/or expressions 
*  $qb = $em->createQueryBuilder(); 
* 
*  $or = $qb->expr()->orx(); 
*  $or->add($qb->expr()->eq('u.id', 1)); 
*  $or->add($qb->expr()->eq('u.id', 2)); 
* 
*  $qb->update('User', 'u') 
*   ->set('u.password', md5('password')) 
*   ->where($or); 
* </code> 
* 
* @param mixed $predicates The restriction predicates. 
* 
* @return QueryBuilder This QueryBuilder instance. 
*/ 
public function where($predicates) 
{ 
    if (! (func_num_args() == 1 && $predicates instanceof Expr\Composite)) { 
     $predicates = new Expr\Andx(func_get_args()); 
    } 

    return $this->add('where', $predicates); 
} 

[从vendor/doctrine/orm/lib/Doctrine/ORM/QueryBuilder]

和add()方法是

/** 
* @param mixed $arg 
* 
* @return Base 
* 
* @throws \InvalidArgumentException 
*/ 
public function add($arg) 
{ 
    if ($arg !== null && (!$arg instanceof self || $arg->count() > 0))  { 
     // If we decide to keep Expr\Base instances, we can use this check 
     if (! is_string($arg)) { 
      $class = get_class($arg); 

      if (! in_array($class, $this->allowedClasses)) { 
       throw new \InvalidArgumentException("Expression of type '$class' not allowed in this context."); 
      } 
     } 

     $this->parts[] = $arg; 
    } 

    return $this; 
} 

[从vendor/doctrine/orm/lib/Doctrine/ORM/Query/Expr/Base]

所以，对我来说，只使用where('foo.id', $someVariable);方法是，当你通过为第二参数表达式如下

$qb->where('su.id = ?1', $qb->expr()->eq('su.somethingElse', '?2')); 

等于

$qb->where('su.id = ?1') 
    ->andWhere('su.somethingElse = ?2'); 

所以，回到谈谈你的问题，如果你想设置的参数，你应该如下

public function buscarConstanciaProducto($solicitudUsuario, $productoSolicitud) 
{ 
    $builder = $this->getEntityManager()->createQueryBuilder(); 
    $builder->select(array('su', 'p', 'ps', 'c')) 
      ->from('AppBundle:SolicitudUsuario', 'su') 
      ->leftJoin('su.producto_solicitud', 'ps') 
      ->leftJoin('ps.producto', 'p') 
      ->leftJoin('su.constancias', 'c') 
      ->where('su.id = ?1') 
      ->andWhere('ps.id = ?2') 
      ->setParameter(1, $solicitudUsuario) 
      ->setParameter(2, $productoSolicitud) 
      ->getQuery() //don't forget this step 
    ; 

    return $builder->getResult(); 
} 

修改查询的构建过程