0
我有这个网址:https://euw.api.riotgames.com/api/lol/EUW/v1.4/summoner/by-name/motschel123?api_key=RGAPI-6A9B210B-31F9-4AD9-8393-1CF3DA6E10EF使用API(RITO API)与Java(Android版)
而且我想在网站上的数据:
try {
URL url = new URL("https://euw.api.riotgames.com/api/lol/" + region + "/v1.4/summoner/by-name/" + summonerN + "?api_key=" + apiCode);
parseJSON(url);
} catch (MalformedURLException e) {
Toast.makeText(getBaseContext(), "Error creating URL",
Toast.LENGTH_LONG).show();
} catch (Exception e) {
Toast.makeText(getBaseContext(), "Error reading URL",
Toast.LENGTH_LONG).show();
}
而且功能parseJSON(URL url)
:
public void parseJSON(URL url) throws Exception{
BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
Toast.makeText(getBaseContext(), inputLine,
Toast.LENGTH_LONG).show();
in.close();
}
但它不起作用,只是抛出一个Exception
。 我该如何解决它?
使用retrofi库创建的getter setter方法,这将是很容易以检索从动态数据url –
@Akashkumar retrofiT? – motschel123
找到下面的答案。我提供 –