在Thunderbird扩展中获取邮件发件人

Question

我正在使用一个非常简单的Thunderbird扩展，它应该在发送邮件时提醒发件人的名称以及收件人的姓名。问题是gMsgCompose.compFields.from字段在下面的代码片段中是空的（.to字段按预期工作），它处理“compose-send-message”事件。我在这里错过了什么？

function send_event_handler(evt) { 
var msgcomposeWindow = document.getElementById("msgcomposeWindow"); 
var msg_type = msgcomposeWindow.getAttribute("msgtype"); 

// do not continue unless this is an actual send event 
if(!(msg_type == nsIMsgCompDeliverMode.Now || msg_type == nsIMsgCompDeliverMode.Later)) 
    return; 

var promptService = Components.classes["@mozilla.org/embedcomp/prompt-service;1"].getService(Components.interfaces.nsIPromptService); 
promptService.alert(window, "From", gMsgCompose.compFields.from); 
promptService.alert(window, "To", gMsgCompose.compFields.to); 
} 

window.addEventListener("compose-send-message", send_event_handler, true); 

Answer 1

您可以通过msgIdentity部件得到发送身份：

var identityWidget = document.getElementById('msgIdentity'); 
var fromIdentityKey= self.identityWidget.value; 

然后，使用客户经理查询身份信息：

var acctMgr = Components.classes["@mozilla.org/messenger/account-manager;1"] 
         .getService(Components.interfaces.nsIMsgAccountManager); 
var accounts = acctMgr.accounts; 
for (var i = 0; i < accounts.Count(); i++) { 
    var account = accounts.QueryElementAt(i, Components.interfaces.nsIMsgAccount); 

    var accountIdentities = account.identities; 

    for(var identCount = 0; identCount < accountIdentities.Count(); identCount++) { 
    var identity = accountIdentities.QueryElementAt(identCount, 
               Components.interfaces.nsIMsgIdentity); 

    if(identity.key == fromIdentityKey) { 
     // Identity found 
     alert(identity.email); 
    } 
    } 
} 

Answer 2

或者在TB 7.0+更方便&简单地如下：

alert(gCurrentIdentity.email); 

不需要getService()并重复，它已经由TB设置，请参阅http://lxr.mozilla.org/comm-central/source/mail/components/compose/content/MsgComposeCommands.js#4052