我有如下表:加盟枢轴TABEL Laravel
食物:
- Foodid(PK)
- FoodName
- FoodImage
- 说明
个分类:
- CATEGORY_ID(PK)
- 类别名称
餐厅
- RES_ID(PK)
- ResName
- 地址
category_food_restaurant
- CATEGORY_ID(FK)
- Food_id(FK)
- RES_ID(FK)
现在我想根据分类名称显示食品项目为此,我将查询设为:
$Category = DB::table('Food')
->select('Food.Food_id','Food.FoodName',
'Food.FoodImage','Categories.CategoryName')
->join('Categories','Categories.Category_id',
'=','category_food_restauarant.Category_id')
->where('Categories.CategoryName',
'=','Breakfast')->get();
但是这给了我错误:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Food.Category_id' in 'on clause' (SQL: select
Food
.Food_id
,Food
.FoodName
,Food
.FoodImage
,Categories
.CategoryName
fromFood
inner joinCategories
onCategories
.Category_id
=Food
.Category_id
whereCategories
.CategoryName
= Breakfast).
凡通过使用这些表根据类别我可以显示食品的problem.How?
它给出错误:SQLSTATE [42S02]:基表或视图未找到:1146表 'foody.category_food_restauarant' 不存在(SQL:选择'Food'.'Food_id', 'Food'.'FoodName','Food'.'FoodImage','Category'.'' CategoryName' from'category_food_restauarant' inner join' Categories' on'Categories'.'Category_id' ='category_food_restauarant'.'Category_id' inner join 'Food' on'Food'.'Food_id' ='category_food_restauarant'.'Food_id' where'Categories'.'CategoryName' = Breakfast) – MANI
我想我误认了表名的拼写。它应该是'category_food_restaurant'。 –
我修改了我的答案。现在检查它... –