我想使用CodeIgniter从数据库检索数据。查询工作正常,并将数据检索到一个数组,可以用print_array()
显示数据。使用codeigniter从数据库中检索数据
Array
(
[0] => Array
(
[trans_id] => 33
[CustomerAccountNumber] => BR002
[TransactionType] => Invoice
[TransactionDate] => 2012-09-06 00:00:00
[InvoiceNo] => 00001732262
[OrderNo] => 0000183946
[GoodsValueInAccountCurrency] => 1055.26
[AccountBalance] => 1104.52
[SYSTraderTranTypeID] => 4
)
[1] => Array
(
[trans_id] => 34
[CustomerAccountNumber] => BR002
[TransactionType] => Invoice
[TransactionDate] => 2012-09-19 00:00:00
[InvoiceNo] => 00001375022
[OrderNo] => 0000184907
[GoodsValueInAccountCurrency] => 49.26
[AccountBalance] => 1104.52
[SYSTraderTranTypeID] => 4
)
)
但每当我试图在表中显示的数据来生成PDF,它给了我一个错误,指出“试图获得非对象的属性”。但是所有的对象都进入了一个数组来显示。这是我的代码:
print_array($data['data']);
{ foreach ($data['data'] as $key=>$link)
{
{
$html .= '
<tr>
<td width = "100">'.$link->InvoiceNo.'</td>
<td width = "300">'.($link->OrderNo).'</td>
<td width = "100">'.($link->TransactionDate).'</td>
<td width = "100">'.($link->TransactionType).'</td>
<td width = "100">'.($link->GoodsValueInAccountCurrency).'</td>
</tr>';
}
}}
但是这给了我错误“试图获得非对象的属性”。我没有得到任何线索。为什么?请帮忙。
Array [(trans_id] => 34 [CustomerAccountNumber] => BAR004 [TransactionType] =>发票[TransactionDate] => 2012-09-19 00:00:00 [InvoiceNo] => 0000175022 [OrderNo] => 0000184907 [GoodsValueInAccountCurrency] => 49.26 [AccountBalance] => 1104.52 [SYSTraderTranTypeID] => 4) – BiL 2013-03-08 11:55:32
尝试使用$ link [“key”]而不是$ link-> key – deadlock 2013-03-08 11:56:13
您可能正在使用CI中的result_array()函数来获取数组。你可以使用result()来获取结果数组作为对象。 – Prashank 2013-03-08 12:03:46