2009-04-20 60 views
0

我有一个表集合有许多实体和一个实体有很多colections ..现在有一个特定的集合有很多实体..如何我可以分页属于一个特定的集合的那些实体..如何分页HABTM数据?

(数组'(实体')),

我发现的查询说.., $ this-> Collection-> find('first',array('condition'=> array('uid'=> $ uid)), ' ))); 现在如何分页实体的结果..

回答

2

在您的控制器动作

$这 - >分页=阵列( '实体'=>数组( '条件'=> “Entity.collection_id = $ ID”, '字段'= > array('Entity。*') ) );

$ this-> set('entities',$ this-> paginate($ this-> Collection-> Entity));

1

我假设你在使用SQL数据库。
现在我还没有测试代码,但我认为它应该工作。

// First query to get some info. 
$testquery = mysql_query("SELECT * FROM `table` WHERE `entity` = 'something'"); 
    if(!$testquery) die(mysql_error()); 

$total_items  = mysql_num_rows($testquery);  // Count the total number of entity's that match the criteria. 
$limit   = 10;  // Maximun number of entity's on page. 
$page    = $_GET['page']; 

//calcuate total pages 
$total_pages  = ceil($total_items/$limit); // ceil is used to round up fractions to the next int 
$set_limit   = $page * $limit - ($limit); 


$query2 = mysql_query("SELECT * FROM `table` WHERE `entity` = 'something' LIMIT $set_limit, $limit"); 
    if(!$query2) die(mysql_error()); 


//show data matching query: 
while($code = mysql_fetch_object($query2)) { 
    echo("item: ".$code->title."<BR>"); 
} 


// This displays the "previous page" link if there is a previous page. 
$prev_page = $page - 1; 
if($prev_page >= 1) { 
    echo("<a href=yourpagename.php?page=$prev_page>Previous</a>"); 
} 


//Display middle pages: 
$mid_page = 1; 
while ($total_pages >= $mid_page) { 
    if ($page == $midpage){ 
     echo ("<b>$mid_page</b> | "); 
    } 
    else { 
     echo (" <a href=yourpagename.php?page=$mid_page> $mid_page </a> | "); 
     $midpage++; 
    } 
} 

// This page will display a "next page" link if there is one. 
$next_page = $page + 1; 
if($next_page <= $total_pages) { 
    echo("<a href=yourpagename.php?page=$next_page>Next</a>"); 
}