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这是什么序列化格式，是否有任何库将其解析回python本地数据结构或至少更容易管理？反向工程通信协议

至少它看起来可能有1：1记者在Python中。

%xt%tableFameUpdate%-1%{"season":[1.329534083671E9,"160",53255],"leaderboard":[["1001:6587656216929005792","1718","Kjeld","http:/..."],["1001:6301086609221020111","802","Asti","http://..."],["1018:995158152656680513","419","QiZOra","http://..."],["1018:8494206166685317681","364","Bingay","http://..."],["1:100000380528383","160","...","http://..."]],"multipliers":{"1001:6835768553933918921":67,"1001:4106589374707547411":0,"1001:5353968490097996024":0,"1018:1168770734837476224":0,"1018:8374571792147098127":0,"1001:4225536539330822139":0,"1:100000380528383":0,"1001:4082457720357735190":68,"1001:1650191466786177826":0,"1001:4299232509980238095":38,"1001:7604050184057349633":0,"1001:6587656216929005792":0,"1001:3852516077423175846":0,"1001:888471333619738847":9,"1001:7823244004315560346":0,"1001:7665905871463311833":0,"1001:4453073160237910447":0,"1001:6338802281112620503":64,"1001:7644306056081384910":13,"1001:4956919992342871722":0,"1001:4126528826861913228":29,"1001:7325864606573096759":47,"1001:6494182198787618518":16,"1001:3678910058012926187":4,"1001:435065490460532259":39,"1001:5366593356123167358":0,"1001:6041488907938219046":8,"1001:6051083835382544277":5,"1001:9187877490300372546":0,"1001:482518425014054339":0}}%

来源

2012-02-18 Flavius

如果你脱掉第一块，最后一个百分号是json，你可以用任何json解析器解析它。它看起来像使用百分号作为迭代器的一种，你可以大大地分裂这些。

来源

2012-02-18 12:56:19 Ryan

大声笑，我怎么没有意识到这一点？谢谢，我会试一试，并在真实数据上进行测试。我会回来的。 – Flavius 2012-02-18 12:58:41

哈哈，脯氨酸一天过得太长，我知道那种感觉。很多时候，我已经睡着了，工作中遇到了问题，或者失去了工作，只能在第二天再回来，并在两秒钟内找出答案。 – Ryan 2012-02-18 13:05:22

是的，它做到了:-) – Flavius 2012-02-18 17:54:01

除了开头的几个字符外，这看起来像JSON。

%xt%tableFameUpdate%-1%不是JSON，但其余的是。有很多用于python的JSON解析器，请选择一个，它应该毫无困难地解析数据。

来源

2012-02-18 12:56:59 Dervall

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