Android：检查空的EditText字段

我正在为个人感兴趣的Android项目工作。我正在处理多个EditText字段，所有字段都必须填入非零的十进制或整数。我在我的xml文件中指定它只接受数字或小数。我对Java不太熟悉，但是我一直在阅读try/catch方法，以及在我试图将每个EditText值解析为double时如何使用它。现在，当所有字段都被填充时，它运行正常，但我想添加某种异常处理，以便如果错误地忘记输入字段，应用程序将显示错误消息而不是崩溃。这听起来很多，但我认为它很小。这是我正在使用的计算方法。感谢您对您的评论:)Android：检查空的EditText字段

public static void calculate() { 

    NumberFormat formatter1 = new DecimalFormat("#0.00"); 
    NumberFormat formatter2 = new DecimalFormat("#0.00000"); 

    Editable evG1F = etG1F.getText(); 
    Editable evG1U = etG1U.getText(); 
    Editable evG2F = etG2F.getText(); 
    Editable evG2U = etG2U.getText(); 
    Editable evG3F = etG3F.getText(); 
    Editable evG3U = etG3U.getText(); 
    Editable evWin = etWin.getText(); 

    double g1f = 0.0; 
    double g1u = 0.0; 
    double g2f = 0.0; 
    double g2u = 0.0; 
    double g3f = 0.0; 
    double g3u = 0.0; 
    double p1odds, p2odds, p3odds, p4odds, p5odds, p6odds, p7odds, p8odds; 
    double totalParlay, profit, finalOdds, risk; 

    win = 0.0; 

    g1f = Double.parseDouble(evG1F.toString()); 
    g1u = Double.parseDouble(evG1U.toString()); 
    g2f = Double.parseDouble(evG2F.toString()); 
    g2u = Double.parseDouble(evG2U.toString()); 
    g3f = Double.parseDouble(evG3F.toString()); 
    g3u = Double.parseDouble(evG3U.toString()); 
    win = Double.parseDouble(evWin.toString()); 

    p1odds = (1/(g1f * g2f * g3f)); 
    p2odds = (1/(g1f * g2f * g3u)); 
    p3odds = (1/(g1f * g2u * g3f)); 
    p4odds = (1/(g1f * g2u * g3u)); 
    p5odds = (1/(g1u * g2f * g3f)); 
    p6odds = (1/(g1u * g2f * g3u)); 
    p7odds = (1/(g1u * g2u * g3f)); 
    p8odds = (1/(g1u * g2u * g3u)); 

    totalParlay = (p1odds + p2odds + p3odds + p4odds + p5odds + p6odds 
      + p7odds + p8odds); 
    profit = 1 - totalParlay; 
    finalOdds = ((profit/totalParlay) + 1); 
    risk = (win/(finalOdds - 1)); 

    p1 = ((risk + win) * p1odds); 
    p2 = ((risk + win) * p2odds); 
    p3 = ((risk + win) * p3odds); 
    p4 = ((risk + win) * p4odds); 
    p5 = ((risk + win) * p5odds); 
    p6 = ((risk + win) * p6odds); 
    p7 = ((risk + win) * p7odds); 
    p8 = ((risk + win) * p8odds); 

    sRisk = risk; 
    sFinalOdds = finalOdds; 

    tvRisk.setText("$" + formatter1.format(Parlay.sRisk)); 
    tvOdds.setText("" + formatter2.format(Parlay.sFinalOdds)); 

}

来源

2012-03-31 user1055656

此代码呼叫阵列。 – MByD 2012-04-01 10:22:45

你可以换你parseDouble()语句在try/catch块：

try { 
     g1f = Double.parseDouble(evG1F.getText().toString()); 
     g1u = Double.parseDouble(evG1U.getText().toString()); 
     g2f = Double.parseDouble(evG2F.getText().toString()); 
     g2u = Double.parseDouble(evG2U.getText().toString()); 
     g3f = Double.parseDouble(evG3F.getText().toString()); 
     g3u = Double.parseDouble(evG3U.getText().toString()); 
     win = Double.parseDouble(evWin.getText().toString()); 
    } catch (NumberFormatException e) { 
     // Error handling here 
    }

，如果它不是一个有效的双重或异常将抛出如果字符串是空的。我在每次通话时在toString()之前添加了getText()，因为您确实无需再声明这些Editable对象（因为您无论如何都只使用getText()）。

来源

2012-03-31 22:26:38

谢谢！我不知道是否需要声明可编辑变量。 – user1055656 2012-04-02 16:08:39

如果我不使用声明的可编辑变量，我认为它应该是etG1F.getText（）。toString（） – user1055656 2012-04-02 17:18:36

你是绝对正确:) – 2012-04-03 21:43:55

Android：检查空的EditText字段

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