连续几天不包括周末SQL 2008

Question

我正在处理不在办公室的报告，正如建议所示，当某人关闭时。我被要求包括返回工作日期。所以我需要编写一个查询来检查这个人关闭的连续日期。我已经设法找到一个接近的查询，但由于周末而绊倒。 所以默认的数据是：

StaffCode HolidayDate 
J.Smith  2017-04-03 00:00:00.000 
J.Smith  2017-04-04 00:00:00.000 
J.Smith  2017-04-05 00:00:00.000 
J.Smith  2017-04-06 00:00:00.000 
J.Smith  2017-04-07 00:00:00.000 
J.Smith  2017-04-10 00:00:00.000 
J.Smith  2017-04-11 00:00:00.000 
J.Smith  2017-04-12 00:00:00.000 
J.Smith  2017-04-13 00:00:00.000 
J.Smith  2017-04-18 00:00:00.000 

当我运行该查询返回

FirstDay   LastDay 
2017-04-03   2017-04-07 
2017-04-10   2017-04-13 
2017-04-18   2017-04-18 

但我要的是

firstDay    lastDay 
2017-04-03    2017-04-13 

这是查询即时通讯使用，是否有排除周末的方法？

WITH t AS (
    SELECT HolidayDate d,ROW_NUMBER() OVER(ORDER BY HolidayDate) i 
    FROM tblHoliday 
    WHERE StaffCode = 'j.Smith' 
     AND HolidayDate >= '27-Feb-2017' 
    GROUP BY HolidayDate 
) 
SELECT MIN(d),MAX(d) 
FROM t 
GROUP BY DATEDIFF(day,i,d) 

Answer 1

这就是Dates表派上用场的地方。有许多博客文章建议将一个Dates表添加到数据库中，用于需要处理日期的情况。

为了创建一个Dates表，你可以使用递归CTE：

;with dates as (
select cast('19000101' as datetime) [current_date] 
union all 
select dateadd(day, 1, current_date) 
from dates 
where current_date <= cast('20991231' as datetime) 
) 
select 
    [current_date] 
    , NULL [holiday] 
    , case datename(weekday, prev_date) 
     when 'Saturday' 
      then 1 
     when 'Sunday' 
      then 1 
     else 0 
    end  [weekend] 
into Dates 
from dates 
option(maxrecursion 0); 

正如你可以看到我添加的，这可能是在未来有帮助的两个额外列。如果某个特定的日子是节假日/国家休息日，则可以包含布尔值以指向 - [holiday]列。

如果一天是周末的一天，第三栏还包含布尔值。

因此，使用Dates表，在一个单一的查询，你可以做这样的事情（这是不漂亮）：

-- I'll also create the sample data and store it into a timeOff table 
create table timeOff (staffCode varchar(25), holidayDate datetime); 

insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-03T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-04T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-05T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-06T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-07T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-10T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-11T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-12T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-13T00:00:00.000' AS DateTime)); 
insert [dbo].[timeOff] ([staffCode], [holidayDate]) values (N'J.Smith', CAST(N'2017-04-18T00:00:00.000' AS DateTime)); 

-- And now for the query itself (it's not pretty but I came up with it in a short time) 

select 
    [staffCode] 
    , min([current_date]) [firstDay] 
    , max([current_date]) [lastDay] 
from 
    (select d.[current_date] 
     , t.staffCode 
     , min(case when d.weekend = 0 and t.holidayDate is null then d.[current_date] else null end) over() [last_date] 
    from 
     (select [staffCode] 
      , min(holidayDate) [mindate] 
      , max(holidayDate) [maxdate] 
     from timeOff t 
     where staffcode = 'J.Smith' 
     group by staffCode) r 
    inner join dates d on d.[current_date] between mindate and maxdate 
    left join timeOff t on d.[current_date] = t.holidayDate) r 
where [current_date] < [last_date] 
    and staffCode is not null 
group by staffCode;