从声明中接收用户输入

Question

我在这里完全失败......逻辑似乎设置正确，但while语句中的“响应”表示它在当前上下文中不存在。我在这里搜索，似乎在这方面找到了同样的问题。问题是否转化为方法？在一个范围（一般一组括号{ ... }的）宣布

do 
     { 
      Console.WriteLine("enter a number between 1 and 5"); 
      int x = Convert.ToInt32(Console.ReadLine()); 

      Random r = new Random(); 
      int rr = r.Next(1, 5); 
      Console.WriteLine("Do you want to continue? Please select yes or no."); 
      string response = Convert.ToString(Console.ReadLine()); 
     } while (response == "yes"); 

Answer 1

变量不是该范围的可访问的外部。您已在内声明response循环。您需要在循环之外声明response。

你也想比较它，使用前String.Trim()从字符串修剪空白。否则，最后会出现换行符（\n），导致比较失败。

string response; 

do { 
    //... 

    response = Console.ReadLine().Trim(); 
} while (response == "yes"); 

Answer 2

您的响应变量不在循环的上下文中。只需将变量声明如下外循环：

 string response = String.Empty; 

     do 
     { 
      Console.WriteLine("enter a number between 1 and 5"); 
      int x = Convert.ToInt32(Console.ReadLine()); 

      Random r = new Random(); 
      int rr = r.Next(1, 5); 
      Console.WriteLine("Do you want to continue? Please select yes or no."); 
      response = Convert.ToString(Console.ReadLine()); 
     } while (response == "yes"); 

Answer 3

可能有助于封装这个有点。如何：

static void Main(string[] args) 
    { 
     Random rand = new Random(); 
     do 
     { 
      Write("enter a number between 1 and 5"); 
      string response = Console.ReadLine(); 
      int x = 5; 
      if (Validate(response, "1-5")) int.TryParse(response, out x);     
      Write(rand.Next(0,x)); 
      Write("Do you want to continue? Please select yes or no.");     
     } while (Validate(Console.ReadLine().ToLower(), "yes")); 
    } 
    static void Write(string s) => Console.WriteLine(s); 
    static bool Validate(string s, string Pattern) => Regex.Match(s, Pattern).Success;