jquery select script node get get

Question

我想从ajax get调用中通过id选择一个脚本节点。

<script id="jqgrid_js" type="text/javascript"> 
... 
</script> 

get调用：

  $.get(url, function(results){ 
       console.debug(results); //the jqgrid_js is included in the result 
       console.debug($('#jqgrid_js')); //this returns the node from the actual page 
       console.debug($('#jqgrid_js', results)); // in the result I can not select it 
       var jqgrid_js = $('#jqgrid_js', results); 
       //do the update 
       $('#jqgrid_js').html(jqgrid_js); 
      }, "html"); 

我想知道为什么同样的SELECT语句不返回节点，而节点肯定是包含在“结果”变种。

Answer 1

尝试扭转这一点，并使用find代替：

var jqgrid_js = $(results).find('#jqgrid_js');