Spring MVC中的WebLogic 10.3.6错误403，禁止

Question

我用Spring MVC的3.2.6.RELEASE和WebLogic 10.3.6和Eclipse朱诺工作

当我执行的应用程序，我想去一个控制器，并得到一个jsp 。

这是我的web.xml

<?xml version="1.0" encoding="UTF-8"?> 
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:jsp="http://java.sun.com/xml/ns/javaee/jsp" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> 
     <display-name>eusurveyadmin</display-name> 


     <servlet> 
      <servlet-name>eusurveyadmin</servlet-name> 
      <servlet-class> 
       org.springframework.web.servlet.DispatcherServlet 
      </servlet-class> 
      <init-param> 
       <param-name>contextConfigLocation</param-name> 
       <param-value> 
       /WEB-INF/spring/eusurveyadmin-servlet.xml 
      </param-value> 
      </init-param> 
      <load-on-startup>1</load-on-startup> 
     </servlet> 
     <servlet-mapping> 
      <servlet-name>eusurveyadmin</servlet-name> 
      <url-pattern>/eusurveyadmin/*</url-pattern> 
     </servlet-mapping> 
     <jsp-config> 
     <taglib> 
      <taglib-uri>http://www.owasp.org/index.php/Category:OWASP_Enterprise_Security_API</taglib-uri> 
      <taglib-location>/WEB-INF/Content/esapi.tld</taglib-location> 
     </taglib> 
     </jsp-config> 

     <context-param> 
     <param-name>log4jConfigLocation</param-name> 
     <param-value>file:ecalcpAdminlog4j.xml</param-value> 
     </context-param> 

<listener> 
    <listener-class> 
     eusurvey.listener.Log4jConfigListener</listener-class> 
</listener> 

<context-param> 
    <param-name>propertiesConfigLocation</param-name> 
     <param-value>file://C://OEPEJUNO//user_projects//domains//test38//configuracion.properties</param-value> 
    </context-param> 
<listener> 

    <listener-class> 
     eusurvey.listener.CustomContextLoaderListener 
    </listener-class> 

</listener> 
<error-page> 
    <error-code>500</error-code> 
    <location>/500</location> 
</error-page> 
<error-page> 
    <error-code>404</error-code> 
    <location>/404</location> 
</error-page> 


</web-app> 

控制器是WelcomeController.java

package eusurvey.controller; 

import java.io.PrintWriter; 
import java.io.StringWriter; 
import java.util.List; 
import java.util.Locale; 

import javax.annotation.Resource; 
import javax.servlet.http.HttpServletRequest; 
import javax.validation.Valid; 

import org.apache.log4j.Logger; 
import org.springframework.stereotype.Controller; 
import org.springframework.ui.Model; 
import org.springframework.ui.ModelMap; 
import org.springframework.validation.BindingResult; 
import org.springframework.web.bind.annotation.ExceptionHandler; 
import org.springframework.web.bind.annotation.ModelAttribute; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.servlet.ModelAndView; 
import org.springframework.web.servlet.mvc.support.RedirectAttributes; 
import org.springframework.web.servlet.view.RedirectView; 

import eusurvey.modelA.daos.Preferencia; 
import eusurvey.services.PreferencesService; 

@Controller 
@RequestMapping("/welcome") 
public class WelcomeController extends ExceptionsController { 
    private static final Logger logger = Logger 
      .getLogger(WelcomeController.class); 

    @Resource(name = "preferencesService") 
    private PreferencesService preferencesService; 

    private int a = 0; 

    private Preferencia results = null; 

    @ModelAttribute("Preferencia") 
    public Preferencia fechaUltimaEncuesta() { 

     results = preferencesService.consultaPreferencia(); 
     return results; 
    } 


    @RequestMapping(value = "/*") 
    public String welcome(HttpServletRequest request, ModelMap model) { 
     logger.info("WelcomeController welcome"); 
     results = fechaUltimaEncuesta(); 
     model.addAttribute("fechaUltimaEncuesta", results.getValor()); 
     request.getSession().setAttribute("fechaUltimaEncuesta", 
       results.getValor()); 
     String fechaUltimaEncuesta = (String) request.getSession() 
       .getAttribute("fechaUltimaEncuesta"); 
     //return "welcome1"; 
     return "/menu/pantallaInicio"; 
    } 

    @ExceptionHandler(Exception.class) 
    public ModelAndView handleException(Exception e, Locale locale, HttpServletRequest request) { 
     logger.error("WelcomeController handleException "+e.getLocalizedMessage()+" exception "+ e); 
     StringWriter sw = new StringWriter(); 
     PrintWriter pw = new PrintWriter(sw); 
     e.printStackTrace(pw); 
     String mensajeException = sw.toString(); 

       logger.error("WelcomeController handleException exception "+e.getClass().getSimpleName()+" mensaje "+mensajeException); 

      ModelAndView mav = new ModelAndView(); 
      mav.addObject("exception", e); 
      mav.addObject("url", request.getRequestURL()); 
      mav.setViewName("errores/errorGeneral"); 
      return mav; 

    } 

} 

当我运行applicacion我得到的错误

这是我的weblogic.xml

<?xml version="1.0" encoding="UTF-8"?> 
<wls:weblogic-web-app 
    xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-web-app" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd http://xmlns.oracle.com/weblogic/weblogic-web-app http://xmlns.oracle.com/weblogic/weblogic-web-app/1.3/weblogic-web-app.xsd"> 
    <wls:weblogic-version>10.3.6</wls:weblogic-version> 
    <wls:context-root>EcalpAdmin</wls:context-root> 
    <wls:container-descriptor> 
     <wls:prefer-web-inf-classes>true</wls:prefer-web-inf-classes> 
    </wls:container-descriptor> 
</wls:weblogic-web-app> 

如何写我的web.xml去控制器？

Answer 1

看起来你的请求映射在类级是/ welcome。任何方法级别的RequestMapping都将与此相关。所以你的网址应该是http://localhost/EcalpAdmin/welcome。