3
我试图抓住一个servlet中的下两个突出显示的字段,我可以获取上传的文件。GWT发送表单参数到一个servlet
的源代码是一样的作为在所示的GWT FormSubmit class Javadoc
form.setEncoding(FormPanel.ENCODING_MULTIPART);
form.setMethod(FormPanel.METHOD_POST);
// Create a panel to hold all of the form widgets.
VerticalPanel panel = new VerticalPanel();
form.setWidget(panel);
// Create a TextBox, giving it a name so that it will be submitted.
final TextBox tb = new TextBox();
tb.setName("WorkTitle");
tb.setValue("WorkTitle");
panel.add(tb);
// Create a ListBox, giving it a name and some values to be associated
// with
// its options.
ListBox lb = new ListBox();
lb.setName("listBoxFormElement");
lb.addItem("foo", "fooValue");
lb.addItem("bar", "barValue");
lb.addItem("baz", "bazValue");
panel.add(lb);
// Create a FileUpload widget.
FileUpload upload = new FileUpload();
upload.setName("uploadFormElement");
panel.add(upload);
// Add a 'submit' button.
panel.add(new Button("Submit", new ClickListener() {
public void onClick(Widget sender) {
form.setAction(GWT.getModuleBaseURL()+"uploadWork");
form.submit();
}
}));
I'm得到这些参数在我的servlet这行代码:
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
System.out.println("ENTRAA BIENNNN");
System.out.println(" ___ELEMENTO1" + req.getAttribute("WorkTitle"));
System.out.println(" ___ELEMENTO3" + req.getParameterValues("WorkTitle"));
但两者返回我NULL
。
我该怎么办?
TIA!
好吧,我明白了。我使用Apache Commons FileUpload,实际上我在服务器端获取文件。问题是我不知道如何包含来自同一表单的文件的标题和评论。 – migueloop
您必须遍历解析的项目并使用'isFormField'。请参阅http://commons.apache.org/fileupload/using.html#Processing_the_uploaded_items或http://commons.apache.org/fileupload/streaming.html#Parsing_the_request –
非常感谢。这个参考帮助了我。 – migueloop