2017-09-13 30 views
0

我之前已经生成了nominatim数据库,并且从未遇到过这样的问题。索引返回关系“search_name_0”在“起始等级2”中不存在

请告诉我哪个“setup.php”命令生成“search_name_0”等表?

完整的错误输出是:

-bash-4.2$ ./utils/setup.php --index --threads 8 --osm2pgsql-cache 24000 
nominatim version 2.5.1 

Starting indexing rank (0 to 4) using 8 threads 
Starting rank 0 
    Done 0 in 0 @ 0.000000 per second - FINISHED 

Starting rank 1 
    Done 0 in 0 @ 0.000000 per second - FINISHED 

Starting rank 2 
index_placex: UPDATE failed: ERROR: relation "search_name_0" does not exist 
LINE 1: DELETE from search_name_0 WHERE place_id = in_place_id 
        ^
QUERY: DELETE from search_name_0 WHERE place_id = in_place_id 
CONTEXT: PL/pgSQL function deletesearchname(integer,bigint) line 1260 at SQL statement 
PL/pgSQL function placex_update() line 75 at assignment 
index_placex: UPDATE failed: ERROR: relation "search_name_0" does not exist 
LINE 1: DELETE from search_name_0 WHERE place_id = in_place_id 
        ^
QUERY: DELETE from search_name_0 WHERE place_id = in_place_id 
CONTEXT: PL/pgSQL function deletesearchname(integer,bigint) line 1260 at SQL statement 
PL/pgSQL function placex_update() line 75 at assignment 
index_placex: UPDATE failed: ERROR: relation "search_name_0" does not exist 
LINE 1: DELETE from search_name_0 WHERE place_id = in_place_id 
        ^
QUERY: DELETE from search_name_0 WHERE place_id = in_place_id 
CONTEXT: PL/pgSQL function deletesearchname(integer,bigint) line 1260 at SQL statement 
PL/pgSQL function placex_update() line 75 at assignment 
index_placex: UPDATE failed: ERROR: relation "search_name_0" does not exist 
LINE 1: DELETE from search_name_0 WHERE place_id = in_place_id 
        ^
QUERY: DELETE from search_name_0 WHERE place_id = in_place_id 
CONTEXT: PL/pgSQL function deletesearchname(integer,bigint) line 1260 at SQL statement 
PL/pgSQL function placex_update() line 75 at assignment 
ERROR: Error executing external command: /srv/Nominatim-2.5.1/nominatim/nominatim -i -d nominatim -P 5432 -t 8 -R 4 
Error executing external command: /srv/Nominatim-2.5.1/nominatim/nominatim -i -d nominatim -P 5432 -t 8 -R 4 

-bash-4.2$ 

回答

0

花了一些时间来弄清楚,但是当你的“创建分区的表”设置的一部分失败,它发生。

重新启动它将无法重新创建表。我不得不手动删除所有的分区表,然后用“create-partition-tables”键重新启动设置来解决这个问题!