所以,我输入了两个字符串,并且在mString中查找了subString。当我将该方法更改为布尔值时,它将返回true或false的正确输出(通过在contains语句中使用返回值)。返回使用'contains'比较两个字符串的结果
我不知道如何使用该语句来检查包含运算符的结果。我已经完成了以下工作。
public class CheckingString
{
public static void main(String[] args)
{
// adding boolean value to indicate false or true
boolean check;
// scanner set up and input of two Strings (mString and subString)
Scanner scan = new Scanner(System.in);
System.out.println("What is the long string you want to enter? ");
String mString = scan.nextLine();
System.out.println("What is the short string that will be looked for in the long string? ");
String subString = scan.nextLine();
// using the 'contain' operator to move check to false or positive.
// used toLowerCase to remove false negatives
check = mString.toLowerCase().contains(subString.toLowerCase());
// if statement to reveal resutls to user
if (check = true)
{
System.out.println(subString + " is in " + mString);
}
else
{
System.out.println("No, " + subString + " is not in " + mString);
}
}
}
有没有办法让检查字段正常工作以返回if-else语句中的值?
卫生署...我无法相信我错过了。很高兴知道布尔if-statmenet。 – user1588867
足够常见,我马上发现它:-)(很多学生都这么做)。至少只有布尔值才会发生。 – TofuBeer