我已经在codeigniter中创建了分页,因为我总共有13条记录,并且我想要在每个页面中显示5条记录。当我在分页链接数2鼠标,它应该在URL传值2,并将其显示在未来5条记录,但我在URL获取而不是2Codeigniter分页没有在URL中传递正确的链接值
值5我的控制器代码:
public function activities($page_num = 1){
$config =array();
$config['base_url'] = base_url().'admin/skills/activities';
$config['per_page'] = 5;
$config['total_rows'] = $this->skill_model->all_activities(0,'',''); // I will get the total count from my model
if(empty($page_num))
$page_num = 1;
$limit_end = ($page_num-1) * $config['per_page']; //end limit
$limit_start = $config['per_page']; // start limit
$this->pagination->first_url = $config['base_url'].'/1';
$this->pagination->initialize($config);
$data['activity_list'] = $this->skill_model->all_activities(1,$limit_start,$limit_end);
}
这是我的看法代码:
<?php echo '<div class="pagination" style="float:right;">'.$this->pagination->create_links().'</div>'; ?>
我Model部分:
function all_activities($flag,$limit_start,$limit_end){
$this->db->select('*');
$this->db->from('skills_activities');
//echo $limit_start." ".$limit_end;
if($flag == 1){
$this->db->limit($limit_start, $limit_end);
$query = $this->db->get();
return $query->result_array();
} else {
$query = $this->db->get();
return $query->num_rows();
}
}
当我点击PAGI国家链接我得到以下网址:
http://192.168.1.97/projects/homecare/admin/skills/activities/5
,但我应该得到:
http://192.168.1.97/projects/homecare/admin/skills/activities/2
我不知道我这样做是错误的。 任何人都可以帮助我吗?
在此先感谢。
$ limit_end =($ PAGE_NUM-1)* $配置[ 'per_page']; // $ limit_end =(1-1)* 5所以结果将会是0 – 2014-12-19 10:42:45
@Rana:是的,第一次是0,所以我会得到限制为0,5 ..下一次page_num将是2,所以(2- 1)* 5 = 5,下5条记录的限制为5,5。 – malar 2014-12-19 10:45:13
so $ this-> skill_model-> all_activities(1,$ limit_start,$ limit_end);将是$ this-> skill_model-> all_activities(1,5,0);将返回0结果 – 2014-12-19 10:49:37