您应该保持viewmodel清洁视图的特定行为。该视图模型应该只是提供一个接口,用于所有相关设置,它可能看起来类似于以下(BaseViewModel
会包含一些辅助的方法来实现INotifyPropertyChanged
等):
public class TeaConfigurationViewModel : BaseViewModel
{
public TeaConfigurationViewModel()
{
_TeaNames = new string[]
{
"Lipton",
"Generic",
"Misc",
};
}
private IEnumerable<string> _TeaNames;
public IEnumerable<string> TeaNames
{
get { return _TeaNames; }
}
private string _SelectedTea;
public string SelectedTea
{
get { return _SelectedTea; }
set { SetProperty(ref _SelectedTea, value); }
}
private bool _IsHotTea;
public bool IsHotTea
{
get { return _IsHotTea; }
set { SetProperty(ref _IsHotTea, value); }
}
private bool _WithMilk;
public bool WithMilk
{
get { return _WithMilk; }
set { SetProperty(ref _WithMilk, value); }
}
private bool _WithLemon;
public bool WithLemon
{
get { return _WithLemon; }
set { SetProperty(ref _WithLemon, value); }
}
private bool _WithSyrup;
public bool WithSyrup
{
get { return _WithSyrup; }
set { SetProperty(ref _WithSyrup, value); }
}
}
正如你看到的,则每个属性设置,但视图模型不关心如何属性被分配。
因此,让我们建立一些用户界面。对于以下示例,通常假设xmlns:local
指向您的项目命名空间。
我建议利用你的目的定制ToggleButton
:
public class MyToggleButton : ToggleButton
{
static MyToggleButton()
{
MyToggleButton.DefaultStyleKeyProperty.OverrideMetadata(typeof(MyToggleButton), new FrameworkPropertyMetadata(typeof(MyToggleButton)));
}
public Brush ToggledBackground
{
get { return (Brush)GetValue(ToggledBackgroundProperty); }
set { SetValue(ToggledBackgroundProperty, value); }
}
// Using a DependencyProperty as the backing store for ToggledBackground. This enables animation, styling, binding, etc...
public static readonly DependencyProperty ToggledBackgroundProperty =
DependencyProperty.Register("ToggledBackground", typeof(Brush), typeof(MyToggleButton), new FrameworkPropertyMetadata());
}
而且在Themes/Generic.xaml
:
<Style TargetType="{x:Type local:MyToggleButton}" BasedOn="{StaticResource {x:Type ToggleButton}}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type local:MyToggleButton}">
<Border x:Name="border1" BorderBrush="Gray" BorderThickness="1" Background="{TemplateBinding Background}" Padding="5">
<ContentPresenter HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"/>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="IsChecked" Value="True">
<Setter TargetName="border1" Property="Background" Value="{Binding ToggledBackground,RelativeSource={RelativeSource TemplatedParent}}"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
现在,建立使用该切换按钮的实际窗口内容。这是你想要的用户界面只是一个粗略的草图,只含无标签和说明功能的控制:
<Grid x:Name="grid1">
<StackPanel>
<StackPanel Orientation="Horizontal">
<ComboBox
x:Name="cb1"
VerticalAlignment="Center"
IsEditable="True"
Margin="20"
MinWidth="200"
ItemsSource="{Binding TeaNames}"
SelectedItem="{Binding SelectedTea}">
</ComboBox>
<local:MyToggleButton
x:Name="hotToggle"
IsChecked="{Binding IsHotTea}"
VerticalAlignment="Center"
Margin="20" MinWidth="60"
Background="AliceBlue" ToggledBackground="Orange">
<local:MyToggleButton.Style>
<Style TargetType="{x:Type local:MyToggleButton}">
<Setter Property="Content" Value="Cold"/>
<Style.Triggers>
<Trigger Property="IsChecked" Value="True">
<Setter Property="Content" Value="Hot"/>
</Trigger>
</Style.Triggers>
</Style>
</local:MyToggleButton.Style>
</local:MyToggleButton>
</StackPanel>
<StackPanel Orientation="Horizontal">
<local:MyToggleButton
x:Name="milkToggle"
Content="Milk"
IsChecked="{Binding WithMilk}"
VerticalAlignment="Center"
Margin="20" MinWidth="60"
Background="WhiteSmoke" ToggledBackground="LightGreen"/>
<local:MyToggleButton
x:Name="lemonToggle"
Content="Lemon"
IsChecked="{Binding WithLemon}"
VerticalAlignment="Center"
Margin="20" MinWidth="60"
Background="WhiteSmoke" ToggledBackground="LightGreen"/>
<local:MyToggleButton
x:Name="syrupToggle"
Content="Syrup"
IsChecked="{Binding WithSyrup}"
VerticalAlignment="Center"
Margin="20" MinWidth="60"
Background="WhiteSmoke" ToggledBackground="LightGreen"/>
</StackPanel>
</StackPanel>
</Grid>
通知样式触发改变Hot
和Cold
之间按钮的内容。
某处初始化DataContext的(如在窗口构造函数)
public MainWindow()
{
InitializeComponent();
grid1.DataContext = new TeaConfigurationViewModel();
}
在这一点上,你有一个全功能的用户界面,它会使用默认的鼠标和键盘输入方法的工作,但它赢得了”还支持你的快捷键。
因此,让我们添加键盘快捷键,而不会破坏已经工作的用户界面。一种方法是,创建和使用一些自定义的命令:
public static class AutomationCommands
{
public static RoutedCommand OpenList = new RoutedCommand("OpenList", typeof(AutomationCommands), new InputGestureCollection()
{
new KeyGesture(Key.B, ModifierKeys.Control)
});
public static RoutedCommand ToggleHot = new RoutedCommand("ToggleHot", typeof(AutomationCommands), new InputGestureCollection()
{
new KeyGesture(Key.T, ModifierKeys.Control)
});
public static RoutedCommand ToggleMilk = new RoutedCommand("ToggleMilk", typeof(AutomationCommands), new InputGestureCollection()
{
new KeyGesture(Key.M, ModifierKeys.Control)
});
public static RoutedCommand ToggleLemon = new RoutedCommand("ToggleLemon", typeof(AutomationCommands), new InputGestureCollection()
{
new KeyGesture(Key.L, ModifierKeys.Control)
});
public static RoutedCommand ToggleSyrup = new RoutedCommand("ToggleSyrup", typeof(AutomationCommands), new InputGestureCollection()
{
new KeyGesture(Key.S, ModifierKeys.Control)
});
}
然后,您可以绑定到相应的操作这些命令在你的主窗口:
<Window.CommandBindings>
<CommandBinding Command="local:AutomationCommands.OpenList" Executed="OpenList_Executed"/>
<CommandBinding Command="local:AutomationCommands.ToggleHot" Executed="ToggleHot_Executed"/>
<CommandBinding Command="local:AutomationCommands.ToggleMilk" Executed="ToggleMilk_Executed"/>
<CommandBinding Command="local:AutomationCommands.ToggleLemon" Executed="ToggleLemon_Executed"/>
<CommandBinding Command="local:AutomationCommands.ToggleSyrup" Executed="ToggleSyrup_Executed"/>
</Window.CommandBindings>
和实施中的每个快捷方式相应的处理方法后面的窗口代码:
private void OpenList_Executed(object sender, ExecutedRoutedEventArgs e)
{
FocusManager.SetFocusedElement(cb1, cb1);
cb1.IsDropDownOpen = true;
}
private void ToggleHot_Executed(object sender, ExecutedRoutedEventArgs e)
{
hotToggle.IsChecked = !hotToggle.IsChecked;
}
private void ToggleMilk_Executed(object sender, ExecutedRoutedEventArgs e)
{
milkToggle.IsChecked = !milkToggle.IsChecked;
}
private void ToggleLemon_Executed(object sender, ExecutedRoutedEventArgs e)
{
lemonToggle.IsChecked = !lemonToggle.IsChecked;
}
private void ToggleSyrup_Executed(object sender, ExecutedRoutedEventArgs e)
{
syrupToggle.IsChecked = !syrupToggle.IsChecked;
}
同样,请记住这整个输入绑定的是纯粹的UI相关的,它只是改变显示PROPERT的另一种方式这些变化将被转移到具有相同绑定的视图模型,就像用户用鼠标点击按钮一样。没有理由将这些东西带入视图模型。
为什么不使用ToggleButton呢?然后,您可以将IsToggled属性绑定到您的数据并随意使用它。 – CKII
您可以将按钮的属性(例如“背景”)绑定到“茶”类的属性。然后使用转换器根据属性的值设置背景颜色。 –
通常,我建议你为你的场景使用'ToggleButton'。然后你可以通过使用'IsChecked'属性来使用MVVM。 – grek40