“美化”/评论问题代码

Question

问题是什么？

如果在其他语句和else语句不起作用的情况下运行if语句，则返回3。

你是什么意思“它不工作”？

int handleArgs(int argc, char *argv[]) { 
    int x = 0; 
    if (argc <= 1) { 
     return x; 
    } 

    x = 1; 

    for (int i = 1; i < argc; i++) { 

     string argument = argv[i];         // Convert argument to string 

     if (argument=="-v" || argument=="--version") {     //*** If user asks for version info ***\\ 
      cout << "\nYou are running \n Dev0.0.0" << endl; 

     } else if (argument == "-a " || argument == "--admin") { //*** If user tries to open console ***\\ 
      cout << "\nSorry, console feature currently unavailable" << endl; 

     } else if (argument=="-h" || argument=="--help") {   //*** If user asks for help ***\\ 

      cout << "\nUsage: " << argv[0] << " -[switch] argument(s)\n"; 
      cout << " -a, --admin  Open console view. Requires password\n"; 
      cout << " -v, --version  Print version and exit\n"; 
      cout << " -h, --help   Print this message and exit\n" << endl; 

     } else { 
      cout << " Is you dumb?\nIncorrect syntax/argument(s)\n '" <<  argv[0] << " --help' for help." << endl; 
     } 
    } 
} 
     return x; 

} 具体来说，if(condition)从不执行，即使条件为真。

第一个else if(condition)也不会执行。

如果为true，则执行第二个else if语句。

的else如果是别的时候真实，

1. 如果声明是真实的执行。
2. 1st else if语句为true。
3. 这些陈述都不是真实的。
4. 如果2nd else if语句为true，则不适用。

摘要

基本上，它就像if和第一else if不存在。

编辑：如果Else语句不工作C++

Answer 1

您的评论未被正确终止。以下作品：

int handleArgs(int argc, char **argv) 
{ 
int x=0; 
if (argc <= 1) {return x;} 
x = 1; 

for (int i=1; i < argc; i++) 
{ 
    string argument(argv[i]);         // Convert argument to string 

    if (argument==std::string("-v") || argument=="--version") 
    { 
     cout << "\nYou are running \n Dev0.0.0" << endl; 
    } 
    else if (argument == "-a " || argument == "--admin") 
    { 
     cout << "\nSorry, console feature currently unavailable" << endl; 
    } 
    else if (argument=="-h" || argument=="--help") 
    {   
     cout << "\nUsage: " << argv[0] << " -[switch] argument(s)\n"; 
     cout << " -a, --admin  Open console view. Requires password\n"; 
     cout << " -v, --version  Print version and exit\n"; 
     cout << " -h, --help   Print this message and exit\n" << endl; 
    } 
    else 
    { 
    cout << " Is you dumb?\nIncorrect syntax/argument(s)\n '" <<  argv[0] << " --help' for help." << endl; 
    } 
} 

Answer 2

如果你行的末尾写\标题已经从”改变，这意味着未来的行将通过预处理器连接起来。然后，将删除包含cout的“声明”的评论。

删除这些垃圾\ s并整齐地格式化您的代码。

#include <iostream> 
#include <string> 
using std::cin; 
using std::cout; 
using std::endl; 
using std::string; 

int handleArgs(int argc, char *argv[]) { 
    int x=0; 
    if (argc <= 1) { 
     return x; 
    } 
    x = 1; 

    for (int i=1; i < argc; i++) { 
     string argument = argv[i];         // Convert argument to string 

     if (argument=="-v" || argument=="--version") {    //*** If user asks for version info *** 
      cout << "\nYou are running \n Dev0.0.0" << endl; 
     } else if (argument == "-a " || argument == "--admin") { //*** If user tries to open console *** 
      cout << "\nSorry, console feature currently unavailable" << endl; 
     } else if (argument=="-h" || argument=="--help") {   //*** If user asks for help *** 
      cout << "\nUsage: " << argv[0] << " -[switch] argument(s)\n"; 
      cout << " -a, --admin  Open console view. Requires password\n"; 
      cout << " -v, --version  Print version and exit\n"; 
      cout << " -h, --help   Print this message and exit\n" << endl; 
     } else { 
      cout << " Is you dumb?\nIncorrect syntax/argument(s)\n '" <<  argv[0] << " --help' for help." << endl; 
     } 
    } 
    return x; 
} 

int main(int argc, char *argv[]) { 
    return handleArgs(argc, argv); 
} 

注：不应该"-a "是"-a"（删除空格）？