2017-02-20 57 views
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的当我运行下面的代码,我得到这个错误消息“的EOFError:跑出输入” 这是什么意思?如何纠正?以及如何在屏幕上输出记录详细信息。的EOFError:跑出输入

import pickle # this library is required to create binary files 
class CarRecord: 
    def __init__(self): 
     self.VehicleID = " "   
     self.Registration = " " 
     self.DateOfRegistration = " " 
     self.EngineSize = 0   
     self.PurchasePrice = 0.00 

ThisCar = CarRecord() 
Car = [ThisCar for i in range(2)]#list of 2 car records 

Car[0].VehicleID = "CD333" 
Car[0].Registration = "17888" 
Car[0].DateOfRegistration = "18/2/2017" 
Car[0].EngineSize = 2500 
Car[0].PurchasePrice = 22000.00 

Car[1].VehicleID = "AB123" 
Car[1].Registration = "16988" 
Car[1].DateOfRegistration = "19/2/2017" 
Car[1].EngineSize = 2500 
Car[1].PurchasePrice = 20000.00 

CarFile = open ('Cars.TXT', 'wb') #open file for binary write 
for j in range (2): # loop for each array element 
    pickle.dump (Car[j], CarFile) # write a whole record to the binary file 
CarFile.close() # close file 

CarFile = open ('Cars.TXT','rb') # open file for binary read 
Car = [] # start with empty list 
while True: #check for end of file 
    Car.append(pickle.load(CarFile)) # append record from file to end of list 
CarFile.close() 
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代码中失败'而TRUE'循环,因为当它到达它试图做数据另一个进程中的数据的结束,它不必须 – WhatsThePoint

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尝试泡菜/ unpickle你'Car'列表直接 –

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该怎么做? – Chris

回答

1

您可以while循环改变你到这一点:

这将break出在输入后,你的while循环的时候临危的EOFError

while True: #check for end of file 
    try: 
     Car.append(pickle.load(CarFile)) # append record from file to end of list 
    except EOFError: 
     break 
CarFile.close() 
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如何在屏幕上打印文件的内容 – Chris

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'json'模块可能会更好地使用,如果你想输出它 – WhatsThePoint