打开图像文件我想执行以下代码错误在PIL
from pytesser import *
import Image
i="C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg"
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text
我收到以下错误
C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg
Traceback (most recent call last):
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\framework\scriptutils.py", line 322, in RunScript
debugger.run(codeObject, __main__.__dict__, start_stepping=0)
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\__init__.py", line 60, in run
_GetCurrentDebugger().run(cmd, globals,locals, start_stepping)
File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\debugger.py", line 655, in run
exec cmd in globals, locals
File "C:\Documents and Settings\Administrator\Desktop\attachments\ocr.py", line 1, in <module>
from pytesser import *
File "C:\Python27\lib\site-packages\PIL\Image.py", line 1952, in open
fp = __builtin__.open(fp, "rb")
IOError: [Errno 2] No such file or directory: 'C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg'
能有人请解释什么,我做错了。
将图像文件重命名。将python文件和图像转移到新文件夹。转移的文件夹,E盘 现在的代码如下:
from pytesser import *
import Image
import os
i=os.path.join("E:\\","ocr","a.jpg")
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text
现在错误如下:
E:\ocr\a.jpg
Traceback (most recent call last):
File "or.py", line 8, in <module>
text = image_to_string(im)
File "C:\Python27\lib\pytesser.py", line 31, in image_to_string
call_tesseract(scratch_image_name, scratch_text_name_root)
File "C:\Python27\lib\pytesser.py", line 21, in call_tesseract
proc = subprocess.Popen(args)
File "C:\Python27\lib\subprocess.py", line 679, in __init__
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 893, in _execute_child
startupinfo)
WindowsError: [Error 2] The system cannot find the file specified
请确保您有正确的路径。 '从操作系统。路径导入isfile;断言isfile(i))'你现在有'print i'的地方。 – AdamKG 2012-03-06 16:11:04
该文件当前是否存在于该位置? – 2012-03-06 16:13:37
是的文件存在。 – Jonah 2012-03-06 16:13:53