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我想解析一个正则表达式的日志文件,我明白拉出IP寻址的第一个,但我坚持如何超越其余部分的日志文件。因此,开始分析剩下的东西,我只是在正则表达式上解析出日期等?所以我会第二个元素是72.37.100.86的第二个IP。然后,我想排除“ - - - ”并将日期作为第4个元素以及“GET/HTTP/1.1:”作为第8个索引以及状态代码200作为第9个索引。任何有关这方面的帮助将非常感谢您了解我接下来要做的事情。试图用正则表达式解析日志文件
package com.text.nginx_log_parser;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegExTester {
// Actual Entry : 10.10.100.151 - 72.37.100.86, 192.36.20.508 - - - [04/Jul/2016:12:50:06 +0000] https https https "GET/HTTP/1.1" 200 20027 "-" "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.107 Safari/537.36"
public static String logEntry = "10.10.100.151 - 72.37.100.86, 192.36.20.508 - - - [04/Jul/2016:12:50:06 +0000] https https https \"GET/HTTP/1.1\" 200 20027 \"-\" \"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.107 Safari/537.36\"\r\n";
//public static String regex = "(\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3})";
//public static String regex = "(\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3})";
public static void main (String [] args){
String regex = "(\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3})\\s*-*\\s*-*\\s*-*";
regexChecker(regex, logEntry);
regex = "\\[*\\]\\s.";
regexChecker(regex, logEntry);
}
public static void regexChecker(String regex, String str){
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(logEntry);
//String firstIP = matcher.group(0);
//String secondIP = matcher.group();
//String timestamp =
while(matcher.find()){
System.out.println(matcher.group(0));
}
}
}
什么输出你期望从这个字符串? –