谷歌分析异步代码

Question

我正在使用Google Analytics的新异步代码，在同一页面调用两次GA.js是否正确，如果不是，有没有办法做到这一点？

我的问题是我需要在使用闪光灯的预订表单上记录两个PageViews，问题在于用户可能不需要进入第二阶段，但在第一阶段关闭窗口。

<!-- Step one, I need to record a pageview --> 

    var _gaq = _gaq || []; 
    _gaq.push(['_setAccount', 'UA-6173481-3']); 
    _gaq.push(['_trackPageview', '/Step1']); 
    (function() { 
    var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true; 
    ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js'; 
    var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s); 
    })(); 

    <!-- Step two of the process i define a function that will get called by flash and record another pageview--> 

    function completed(){ 

    var _gaq = _gaq || []; 
    _gaq.push(['_setAccount', 'UA-6173481-3']); 
    _gaq.push(['_trackPageview', '/Step2']); 
    (function() { 
    var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true; 
    ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js'; 
    var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s); 
    })(); 

    } 

Answer 1

下面应该工作：

<!-- Step one, I need to record a pageview --> 
    var _gaq = _gaq || []; 
    _gaq.push(['_setAccount', 'UA-6173481-3']); 
    _gaq.push(['_trackPageview', '/Step1']); 
    (function() { 
    var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true; 
    ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js'; 
    var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s); 
    })(); 

    <!-- Step two of the process i define a function that will get called by flash and record another pageview--> 
    function completed(){ 
    _gaq.push(['_trackPageview', '/Step2']);  
    } 

然后从闪存需要时调用completed()。