我记得,我bean定义是这样的,并且工作正常程序化记得,我与春天secruity
<security:remember-me data-source-ref="dataSource" user-service-ref="userService"/>
然而,用户第一次注册,我想以编程方式记录他们并执行一记-我。我不知道如何访问Remember-me服务。我能做到这一点
UsernamePasswordAuthenticationToken auth =
new UsernamePasswordAuthenticationToken(user, "", authorities);
SecurityContextHolder.getContext().setAuthentication(auth);
HttpServletRequestWrapper wrapper = new HttpServletRequestWrapper(request) {
@Override public String getParameter(String name) { return "true"; }
};
但是如何访问记住我服务象下面这样,因为我使用的是默认的弹簧实现,而不是我自己的豆?
getRememberMeServices().loginSuccess(wrapper, response, auth);
从here
编辑 我已经改变了我的bean定义看起来像这样
<security:remember-me services-alias="rememberMeService" data-source-ref="dataSource" user-service-ref="userService"/>
不过的IntelliJ仍然回来同一个错误,当我尝试这样的注入:
@Resource(name = "rememberMeService")
private RememberMeServices rememberMeService;
试着替换_ @ Resource_ by _ @ Inject_或_ @ Autowired_ – 2013-02-11 09:48:05