把多个值到json_encode

Question

我使用多个SQL查询的数组，然后使用foreach循环运行查询：

foreach($sql as $query) { 
    $rs=mysql_query($query, $conn); 
    if(mysql_num_rows($rs) > 0){ 
     while($result=mysql_fetch_assoc($rs)) { 
      $json_arr["id"] = $result['sequence']; 
      $json_arr["value"] = $result['company']; 
      $json_arr["label"] = $result['company']; 
      array_push($display_json, $json_arr); 
     } 
    } else { 
     $json_arr["id"] = "#"; 
     $json_arr["value"] = ""; 
     $json_arr["label"] = "No Result Found!"; 
     array_push($display_json, $json_arr); 
    } 
} 

然后我需要使用json_encode并打印结果，如：

$jsonWrite = json_encode($display_json); //encode that search data 
print $jsonWrite; 

我该如何为所有查询结果做一个json_encode？

Answer 1

foreach($sql as $query) { 
    $rs=mysql_query($query, $conn); 
    if(mysql_num_rows($rs) > 0){ 
     while($result=mysql_fetch_assoc($rs)) { 
      $json_arr["id"] = $result['sequence']; 
      $json_arr["value"] = $result['company']; 
      $json_arr["label"] = $result['company']; 

     } 
     array_push($display_json, $json_arr); 
    } else { 
     $json_arr["id"] = "#"; 
     $json_arr["value"] = ""; 
     $json_arr["label"] = "No Result Found!"; 
     array_push($display_json, $json_arr); 
    } 
} 

将第一个array_push移动到while循环之外，如上所述，将防止您看到的重复。