2
我有一个动物模式:猫鼬找到方法后,创建
const AnimalSchema = new mongoose.Schema({
type: { type: String, default: "goldfish" },
size: String,
color: { type: String, default: "golden" },
mass: { type: Number, default: 0.007 },
name: { type: String, default: "Angela" }
});
动物实验数据数组:
let animalData = [
{
type: 'mouse',
color: 'gray',
mass: 0.035,
name: 'Marvin'
},
{
type: 'nutria',
color: 'brown',
mass: 6.35,
name: 'Gretchen'
},
{
type: 'wolf',
color: 'gray',
mass: 45,
name: 'Iris'
}
];
然后我试图清空在动物模型中的所有数据,保存阵列数据库,记录一些动物实验数据和关闭连接:
Animal
.remove({})
.then(Animal.create(animalData))
.then(Animal.find({}).exec())
.then(animals => {
animals.forEach(animal => console.log(`${animal.name} is ${animal.color} ${animal.type}`))
})
.then(() => {
console.log('Saved!');
db.close().then(() => console.log('db connection closed'));
})
.catch((err) => {
console.error("Save Failed", err);
});
但是,当我试图执行此我得到一个错误: 保存失败类型错误:animals.forEach是不是Animal.remove.then.then.then.animals功能 (C:_projects \ express_api \ mongoose_sandbox.js:89:12)
这有什么错我的代码和如何使它工作?谢谢。