简单如果其他声明。

Question

试图让这个工作..我不明白If If语句。基本上，如果场照片有一个值，我希望它显示，如果它的值为Null显然会显示其他语句。 ！

$row = photo 

$id = $_GET['id']; 
$sql = "SELECT * FROM menu_category WHERE id = '$id' order by sort"; 
$query = mysql_query($sql); 
while($row = mysql_fetch_array($query)) { 

echo " <h1>".$row['category_field']."</h1> "; 
echo "<div class=\"itemdescription\"> ".$row['description']."</div> "; 

$row = photo("*"); 

if ($photo = "*") { 
echo "Have a good day!"; 
} else { 
echo "Have a good night!"; 
} 

Answer 1

使用空，以检查是否存在照片与否，不是*

$row = photo 

$id = $_GET['id']; 
$sql = "SELECT * FROM menu_category WHERE id = '$id' order by sort"; 
$query = mysql_query($sql); 
while($row = mysql_fetch_assoc($query)) { 
$photo_exist = $row['photo']; 

echo " <h1>".$row['category_field']."</h1> "; 
echo "<div class=\"itemdescription\"> ".$row['description']."</div> "; 



if (!empty($photo_exist)) { 
echo "Have a good day!"; 
} else { 
echo "Have a good night!"; 
}