Django-rest-framework创建具有多对多关系的对象

Question

我需要创建具有多对多连接到对象“任务”的关系的对象“标记”。我拥有此代码，并且不明白为什么它不会没有工作。我看到错误无法将关键字“任务”解析到字段中。选择是：id，名称，标签， P.S. 我靠这个帖子manyToMany with django rest framework

.models

class Tag(models.Model): 
    name = models.CharField(max_length=200) 
    def __str__(self): 
     return "{}".format(self.name) 

class Task(models.Model): 
    name = models.CharField(max_length=200, blank=True) 
    tags = models.ManyToManyField(Tag) 
    def __str__(self): 
     return "{}".format(self.name) 

.views

class TagCreateView(generics.ListCreateAPIView): 
    serializer_class = TagSerializer 

    def get_queryset(self): 
     queryset = Tag.objects.all() 
     task_id = self.kwargs.get('task_id', None) 
     if task_id is not None: 
      queryset = queryset.filter(task=task_id) 
     return queryset 
    def perform_create(self, serializer): 
     task_id = self.kwargs.get('task_id', None) 
     try: 
      tasks = Task.objects.get(task__id__exact=task_id) 
     except Task.DoesNotExist: 
      raise NotFound() 
     serializer.save(tag=tasks) 

.serielizers

class TagSerializer(serializers.ModelSerializer): 
    class Meta: 
     model = Tag 
     fields = ('id', 'name','') 

class TaskSerializer(serializers.ModelSerializer): 
    tag = TagSerializer(many=True, read_only=True) 
    class Meta: 
     model = Task 
     fields = ('id', 'name', 'tags') 
     read_only_fields = ('tags') 

.urls

urlpatterns = { 
url(r'^todolists/(?P<task_id>[0-9]+)/tags', TagCreateView.as_view(), name="tags")} 

Answer 1

您需要处理串行器create方法中创建的嵌套序列器;

正如在这里：http://www.django-rest-framework.org/api-guide/serializers/#writing-create-methods-for-nested-representations