我遇到了一些简单问题。我将在HTTPServlet中获得真实客户端IP。在Servlet中获取真正的客户端IP
因为现在我用:
request.getRemoteAddr()
但现在它返回假的IP。例如:xxx.xxx.xxx。 但我的IP是像xxx.xxx.xxx。 。 (在http://whatismyipaddress.com/处检查)。
现在我试着使用:
request.getHeader("X-Forwarded-For")
返回null。
我还参加了探头下面的类:
public class IpUtils {
public static final String _255 = "(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)";
public static final Pattern pattern = Pattern.compile("^(?:" + _255 + "\\.){3}" + _255 + "$");
public static String longToIpV4(long longIp) {
int octet3 = (int) ((longIp >> 24) % 256);
int octet2 = (int) ((longIp >> 16) % 256);
int octet1 = (int) ((longIp >> 8) % 256);
int octet0 = (int) ((longIp) % 256);
return octet3 + "." + octet2 + "." + octet1 + "." + octet0;
}
public static long ipV4ToLong(String ip) {
String[] octets = ip.split("\\.");
return (Long.parseLong(octets[0]) << 24) + (Integer.parseInt(octets[1]) << 16)
+ (Integer.parseInt(octets[2]) << 8) + Integer.parseInt(octets[3]);
}
public static boolean isIPv4Private(String ip) {
long longIp = ipV4ToLong(ip);
return (longIp >= ipV4ToLong("10.0.0.0") && longIp <= ipV4ToLong("10.255.255.255"))
|| (longIp >= ipV4ToLong("172.16.0.0") && longIp <= ipV4ToLong("172.31.255.255"))
|| longIp >= ipV4ToLong("192.168.0.0") && longIp <= ipV4ToLong("192.168.255.255");
}
public static boolean isIPv4Valid(String ip) {
return pattern.matcher(ip).matches();
}
public static String getIpFromRequest(HttpServletRequest request) {
String ip;
boolean found = false;
if ((ip = request.getHeader("x-forwarded-for")) != null) {
StringTokenizer tokenizer = new StringTokenizer(ip, ",");
while (tokenizer.hasMoreTokens()) {
ip = tokenizer.nextToken().trim();
if (isIPv4Valid(ip) && !isIPv4Private(ip)) {
found = true;
break;
}
}
}
if (!found) {
ip = request.getRemoteAddr();
}
return ip;
}
}
它还返回xxx.xxx.xxx.50 IP。 :(
现在我不servlet容器之前,知道如何获得真正的客户端IP。如果有人知道解决方案请回答。
是您的服务器直接连接到互联网?有没有路由器,负载均衡器,NAT设备等? – mindas 2013-04-23 09:03:14
只有一个ruter。 – TAR515 2013-04-23 17:49:56