将两个表与mysql中的一组条件结合起来

Question

我有三张表（doctor，clinic_doctor_timings，hosptial_doctor_timings）。时间表中包含医生表的ID作为外键，还存储医生的时间和时间。现在我需要选择在给定时间内去往诊所或医院的医生ID，即从和到。

我写了一个查询，可用于诊所或医院，但不是两者兼而有之。

SELECT 
DISTINCT 
SQL_CALC_FOUND_ROWS 
`doctor`.`id`, 
`doctor`.`name` 
FROM 
`doctor` 
JOIN clinic_doctor_timings AS cl 
ON cl.doctor_id = doctor.id 
WHERE 
TIME_FORMAT(`cl`.`from`, %h:%i %p) >= '05:00 AM' 
AND TIME_FORMAT(`cl`.`to`, %h:%i %p) >= '10:00 PM' 

上述查询工作正常，但之后，我想无论是clinic_doctor_timings和hospital_doctor_timings表结合我没有得到结果我的期望。

......... 
JOIN clinic_doctor_timings AS cl 
ON cl.doctor_id = doctor.id 
JOIN hospital_doctor_timings AS hs 
ON hs.doctor_id = doctor.id 
WHERE 
(TIME_FORMAT(`cl`.`from`, %h:%i %p) >= '05:00 AM' 
AND TIME_FORMAT(`cl`.`to`, %h:%i %p) <= '10:00 PM') 
XOR 
(TIME_FORMAT(`hs`.`from`, %h:%i %p) >= '05:00 AM' 
AND TIME_FORMAT(`hs`.`to`, %h:%i %p) <= '10:00 PM') 

我需要为诊所和医院提供诊所和医院以外的给定时间。

Answer 1

获取谁去诊所医生：

SELECT a.id, a.name FROM doctor a 
INNER JOIN clinic_doctor_timings b ON a.id = b.doctor_id 
WHERE 
b.`from` >= '2013-05-02 05:00:00' AND 
b.`to` <= '2013-05-02 22:00:00'; 

获取谁去医院医生：

SELECT a.id, a.name FROM doctor a 
INNER JOIN hospital_doctor_timings b ON a.id = b.doctor_id 
WHERE 
b.`from` >= '2013-05-02 05:00:00' AND 
b.`to` <= '2013-05-02 22:00:00'; 

获取谁去诊所和医院

SELECT a.id, a.name FROM doctor a 
INNER JOIN clinic_doctor_timings b ON a.id = b.doctor_id 
INNER JOIN hospital_doctor_timings c ON a.id = c.doctor_id 
WHERE 
b.`from` >= '2013-05-02 05:00:00' AND 
b.`to` <= '2013-05-02 22:00:00' AND 
c.`from` >= '2013-05-02 05:00:00' AND 
c.`to` <= '2013-05-02 22:00:00'; 

医生得到去诊所的医生或医院

SELECT a.id, a.name FROM doctor a 
WHERE 
(
    SELECT COUNT(b.id) FROM clinic_doctor_timings b WHERE 
    b.doctor_id = a.id and 
    b.`from` >= '2013-05-02 05:00:00' AND 
    b.`to` <= '2013-05-02 22:00:00' 
) > 0 
or 
(
    SELECT COUNT(c.id) FROM hospital_doctor_timings c WHERE 
    c.doctor_id = a.id and 
    c.`from` >= '2013-05-02 05:00:00' AND 
    c.`to` <= '2013-05-02 22:00:00' 
) > 0; 

这还不够得到你想要的吗？