将POST数据从Objective-C传递到PHP

我试图将一些POST数据从Objective-c传递到PHP，但PHP文件似乎没有获取数据。将POST数据从Objective-C传递到PHP

下面是我送它：

- (void) sendJSONData:(NSDictionary *)dictData { 

    NSError *error; 

    NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration]; 
    NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil]; 
    NSURL *url = [NSURL URLWithString:kRootWebService]; 
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url 
                  cachePolicy:NSURLRequestUseProtocolCachePolicy 
                 timeoutInterval:60.0]; 

    [request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"]; 
    [request addValue:@"application/json" forHTTPHeaderField:@"Accept"]; 

    [request setHTTPMethod:@"POST"]; 
    NSDictionary *mapData = [[NSDictionary alloc] initWithObjectsAndKeys: @"TEST IOS", @"name", 
          @"IOS TYPE", @"typemap", 
          nil]; 
    NSData *postData = [NSJSONSerialization dataWithJSONObject:mapData options:0 error:&error]; 
    [request setHTTPBody:postData]; 

    NSLog(@" URL: %@", request); 
    NSLog(@" Body: %@", [[NSString alloc] initWithData:request.HTTPBody encoding:NSUTF8StringEncoding]); 

    NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) { 

     NSHTTPURLResponse* httpResponse = (NSHTTPURLResponse*) response; 
     NSLog(@"%@", httpResponse.allHeaderFields); 
     if (httpResponse.statusCode == 200) { 

      NSString *str = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]; 
      NSLog(@"This is my print out of data to string\n%@",str); 

      //deseriealize the return 
      id JSONObject = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error]; 

      NSDictionary* dictJSON; 
      NSArray* arrJSON; 

      NSLog(@"%@", dictJSON); 

     } else { 

      NSLog(@"There was an error connecting with the server, the status code returned was %i", (int)httpResponse.statusCode); 

     } 

    }]; 

    [postDataTask resume]; 


}

这里的URL的日志（网址是正确的）和身体：

URL: http://xxxxxxxx.com/xxxxxx.php } 
2017-07-30 15:20:10.602 MirrorBox[89680:5646406] Body: {"name":"TEST IOS","typemap":"IOS TYPE"}

这里的请求头的日志

2017-07-30 15:20:10.751 MirrorBox[89680:5646478] { 
    Age = 0; 
    Connection = "keep-alive"; 
    "Content-Length" = 34; 
    "Content-Type" = "text/html"; 
    Date = "Sun, 30 Jul 2017 19:20:10 GMT"; 
    Server = "Apache/2"; 
    "X-Powered-By" = "PHP/5.5.22"; 
}

这是返回数据的日志，错误信息是我自己的：

This is my print out of data to string 
{"key":"could not read POST data"}

这里是PHP文件：

<?php 

    if (!$_POST['IOS_TYPE']) { 
     echo json_encode(array("key" => "could not read POST data")); 
    } else { 
     echo json_encode(array("key" => "returned string")); 
    } 


?>

来源

2017-07-30 PruitIgoe

如果你通过与主要的帖子..你应该使用相同的密钥访问

<?php 

    if (!$_POST['typemap']) { 
     echo json_encode(array("typemap" => "could not read POST data")); 
    } else { 
     echo json_encode(array("typemap" => "returned string")); 
    } 


?>

或更好

if (isset($_POST['typemap'])){ 
    if ($_POST['typemap'] == 'IOS TYPE') { 
      echo 'IOS TYPE type in typemap POST'; 
    } 
} 
    .....

来源

2017-07-30 19:29:02 scaisEdge

我应该提到我有这样的较早，想，也许我是倒着读的钥匙，但我这样做是因为在你的答案我仍然不要击中$ _POST数据 – PruitIgoe

尝试var_dump（$ _ POST）并检查真实内容.. – scaisEdge

它是一个空数组 – PruitIgoe

由于您在请求的主体中传递了JSON，请尝试以下方法：

$content = file_get_contents('php://input'); 
$obj  = json_decode($content , false);  // decode to stdObj 
$typemap = $obj->typemap;

，或者如果你喜欢用关联数组工作：

$ary  = json_decode($content , true);  // decode to array 
$typemap = $ary['typemap'];

来源

2017-07-30 19:46:13 YvesLeBorg

谢谢，那正是我所需要的。 – PruitIgoe

我的荣幸...还有，不要工作PHP盲人，与良好的IDE工作！ – YvesLeBorg

我正在写一个iOS应用程序，只需要能够将用户设置存储到后端。我写了任何PHP已经有好几年了，而且我显然生疏了。我正在Coda编写代码，所以我应该更多地考虑调试。 – PruitIgoe

将POST数据从Objective-C传递到PHP

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