从Sql Server Express 2005中检索结构化的XML

Question

我想从下面的全文搜索索引表中获得xml输出。但我的代码产生近工会 我的代码不正确的语法

SELECT 
Table1.Name 'Table1/Name', 
Table1.Email 'Table1/Email', 
( SELECT 
    Table2.Address 'Address', 
    Table2.Phone 'Phone', 
    FROM Details Table2 
    INNER JOIN Regd Table3 ON Table3.Code = Table2.Code 
    AND (Table3.SubCode = xml.SubCode) AND (Table1.Id = Table3.Id) 
    FOR XML PATH ('Details'),Type) as 'Table1', 
FROM Users Table1 
INNER JOIN CONTAINSTABLE(Users,[Name], @SearchKeys) AS KEY_TBL ON Id = KEY_TBL.[KEY] 
INNER JOIN Regd Table3 ON Table3.Id = Table1.Id, 
OPENXML (@idoc,'/Request/List',2) 
WITH (SubCode NVARCHAR(20)) as xml 
WHERE (xml.SubCode = '' or Table3.SubCode = xml.SubCode) AND (Table3.Id = Table1.Id) 
FOR XML PATH ('List') 
UNION 
SELECT 
SELECT 
Table1.Name 'Table1/Name', 
Table1.Email 'Table1/Email', 
( SELECT 
    Table2.Address 'Address', 
    Table2.Phone 'Phone', 
    FROM Details Table2 
    INNER JOIN Regd Table3 ON Table3.Code = Table2.Code 
    AND (Table3.SubCode = xml.SubCode) AND (Table1.Id = Table3.Id) 
    FOR XML PATH ('Details'),Type) as 'Table1', 
FROM Users Table1 
INNER JOIN CONTAINSTABLE(Users,[Email], @SearchKeys) AS KEY_TBL ON Id = KEY_TBL.[KEY] 
INNER JOIN Regd Table3 ON Table3.Id = Table1.Id, 
OPENXML (@idoc,'/Request/List',2) 
WITH (SubCode NVARCHAR(20)) as xml 
WHERE (xml.SubCode = '' or Table3.SubCode = xml.SubCode) AND (Table3.Id = Table1.Id) 
FOR XML PATH ('List') 

这里出来把我预计将有

<List> 
<Table1> 
<Name></Name> 
<Email></Email> 
<Details> 
<Address></Address> 
<Phone></Phone> 
</Details> 
</Table1> 
</List> 

我想请求XML参数不会有任何用处的这里，因为它是只是一个语法错误

Answer 1

你的代码中有很多语法错误，但我认为他们在那里，因为你已经删除了很多你认为没有必要的东西。

你说你得到的错误是Incorrect syntax near the keyword 'union'。

这会给你的错误，

select * 
from YourTable 
for xml path('list') 
union 
select * 
from YourTable 
for xml path('list') 

你必须嵌入查询，在这样的select语句。

select 
(select * 
from YourTable 
for xml path('list')) 
union 
select 
(select * 
from YourTable 
for xml path('list')) 

如果你想要的列是XML类型的，你需要添加type和使用union all因为The xml data type cannot be selected as DISTINCT because it is not comparable.

select 
(select * 
from YourTable 
for xml path('list'), type) 
union all 
select 
(select * 
from YourTable 
for xml path('list'), type) 

我不知道，如果这最终会给你你想要的输出，但此是Incorrect syntax near the keyword 'union'的原因以及您可以对此做些什么。