1
我正在看MDN's "Using native JSON"。我有3个关于JSON.stringify
方法的问题。关于ECMAScript中JSON.stringify的问题
问题1:
var foo = {
"foundation": "Mozilla",
"model": "box",
"week": 45,
"transport": "car",
"month": 7
},
censor = function (key, value) {
if (typeof value === 'string') {
return;
}
return value;
};
console.log(JSON.stringify(foo, censor)); // String: {"week":45,"month":7}
以上验证码做工精细。但为什么下面的代码不能正常工作?
var foo = {
"foundation": "Mozilla",
"model": "box",
"week": 45,
"transport": "car",
"month": 7
},
censor = function (key, value) {
if (typeof value !== 'string') {
return;
}
return value;
};
console.log(JSON.stringify(foo, censor)); // undefined
问题2:
请注意下面的代码:
var foo = {
"foundation": "Mozilla",
"model": "box",
"week": 45,
"transport": "car",
"month": 7
},
censor = function (key, value) {
return 2;
};
console.log(JSON.stringify(foo, censor)); // String: 2
我想我的代码应该得到下面的字符串,因为“如果返回一个数字,对应于这个数字的字符串用作添加到JSON字符串时属性的值。“ (从https://developer.mozilla.org/En/Using_native_JSON引用)。
{"foundation":2,"model":2,"week":2,"transport":2,"month":2}
但我只是得到一个字符串2
。为什么?
问题3:
如果我想获得{"foundation":2,"model":2,"week":2,"transport":2,"month":2}
,我应该怎么更改密码?
非常感谢!