试图将2个模型合并到我的“季节”视图/模板上我的Django站点上。目前,我将以下内容视为ValueError“视图webapp.views.season没有返回HttpResponse对象,而是返回None。”不知道我在做什么错,但希望有人可以看看。Django中单个视图/模板上的多个模型
views.py
from django.shortcuts import render, get_object_or_404, redirect
from django.views.generic import ListView
from .models import Player, Season
def home(request):
seasons = Season.objects.order_by('sid')
return render(request, 'webapp/home.html', {'seasons': seasons})
def player(request, pk):
player = get_object_or_404(Player, pk=pk)
return render(request, 'webapp/player.html', {'player': player})
def season(ListView, pk):
model = Season
template_name = 'webapp/season.html'
def get_context_data(self, **kwargs):
context = super(season, self).get_context_data(**kwargs)
context['players'] = Player.objects.all()
return context
def seasons(request):
seasons = Season.objects.order_by('sid')
return render(request, 'webapp/seasons.html', {'seasons': seasons})
urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.home, name='home'),
url(r'^player/(?P<pk>\d+)/$', views.player, name='player'),
url(r'^season/(?P<pk>\d+)/$', views.season, name='season'),
url(r'^seasons/$', views.seasons, name='seasons'),
]
应当指出的是,我本来有一个类型错误,上面写着 “季节()得到了一个意想不到的关键字参数 'PK'” 前我将pk添加到了季节的参数中。任何帮助是极大的赞赏!谢谢!
所以这得到它的阶级基础观点页面,但显示每个季节,而不仅仅是他们所附的季节。我如何限制它只是球员所属的赛季?目前,我有第三个模型,它具有Player和Season模型的外键。我认为我需要将它们连接起来,但不知道如何编码。 – SepticReVo