Sqlite返回不同​​的值 - iOS

Question

当调用相同的'DBName'值时，下面的函数返回不同的bool值。我期待着找到重复。在第一次尝试它的工作和第二次尝试它没有。我做错了什么？

-(BOOL)CheckForDB:(NSString *)dbPath{ 
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) { 
    if(checkForDB == nil){ 

     const char *sql = "SELECT COUNT(*) FROM BookingInfo WHERE DBName = ?"; 
     if(sqlite3_prepare_v2(database, sql, -1, &checkForDB, NULL) != SQLITE_OK) { 
      NSAssert1(0, @"Error while fetching uploaded status. '%s'", sqlite3_errmsg(database)); 
     } 
    } 

    sqlite3_bind_text(checkForDB, 1, [dbName UTF8String], -1, SQLITE_TRANSIENT); 

      NSLog(@"checking status %@",dbName); 
    while(sqlite3_step(checkForDB) == SQLITE_ROW) { 



     NSString *status=[NSString stringWithUTF8String:(char *)sqlite3_column_text(checkForDB, 0)]; 
     return [status boolValue]; 
    } 

    return NO; 
    sqlite3_reset(checkForDB); 


}else{ 
    sqlite3_close(database); 
    } 
} 

Answer 1

我找到了解决方案。我要打电话sqlite3_reset（checkForDB）一个更多的时间之前，我打电话回YES

while(sqlite3_step(checkForDB) == SQLITE_ROW) { 



    NSString *status=[NSString stringWithUTF8String:(char *)sqlite3_column_text(checkForDB, 0)]; 
    sqlite3_reset(checkForDB) 
    return [status boolValue]; 
}