如何捕获两个文件的FileNotFoundException？

Question

我有两个文本文件，我想抛出一个异常，如果没有找到文件。我有一个类FileReader，检查文件是否存在，并在我的主要我试图捕捉异常。

public FileReader() throws FileNotFoundException { 
     super(); 
     File file1 = new File("file1.txt"); 
     File file2 = new File("file2.txt"); 

     //Throws the FileNotFoundException if the files aren't found 
     if (!file1.exists()) { 
      throw new FileNotFoundException("File \"file1.txt\" was not found."); 
     } else { 
     //do something 
     } 
     if (!file2.exists()) { 
      throw new FileNotFoundException("File \"file2.txt\" was not found."); 
     } else { 
     //do something 
     } 

在另一个类中，我想捕捉异常如果文件丢失。

public class FileIO { 

public static void main(String[] args) { 

    try { 
     //do stuff 
    } catch(FileNotFoundException e) { 
     System.out.println(e.getMessage()); 
    } 

如果只有一个文件丢失，这很有用。但是，如果file1和file2都丢失了，我只会捕获第一个丢失文件的异常，然后程序结束。我的输出是：

File "file1.txt" is not found. 

我该如何捕捉两者的例外？我想要它输出：

File "file1.txt" is not found. 
File "file2.txt" is not found. 

Answer 1

您可以在抛出异常之前构造错误消息。

public FileReader() throws FileNotFoundException { 
    super(); 
    File file1 = new File("file1.txt"); 
    File file2 = new File("file2.txt"); 

    String message = ""; 

    if (!file1.exists()) { 
     message = "File \"file1.txt\" was not found."; 
    } 
    if (!file2.exists()) { 
     message += "File \"file2.txt\" was not found."; 
    } 

    //Throws the FileNotFoundException if the files aren't found 
    if (!messag.isEmpty()) { 
     throw new FileNotFoundException(message); 
    } 

    //do something