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我正尝试在他们的本机API上对Blackberry使用RSA加密。我在Java中创建了公钥/私钥对,并将密钥的模数和指数保存为字符串,这样我就可以从中生成用于加密和解密的密钥。下面的代码是从客户端,我得到一个InvalidKeyException
和回溯是空,因此我不知道发生了什么事:在BlackBerry上使用RSA加密时出错
public byte[] Encrypt(byte[] data)
{
try {
RSACryptoSystem cryptoSystem = new RSACryptoSystem(1024);
RSAPublicKey publicKey = new RSAPublicKey(cryptoSystem, _publicKeyExponent.getBytes(), _publicKeyModulus.getBytes());
RSAEncryptorEngine encryptorEngine = new RSAEncryptorEngine(publicKey);
PKCS5FormatterEngine formatterEngine = new PKCS5FormatterEngine(encryptorEngine);
ByteArrayOutputStream output = new ByteArrayOutputStream();
BlockEncryptor encryptor = new BlockEncryptor(formatterEngine, output);
encryptor.write(data);
encryptor.close();
output.close();
return output.toByteArray();
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
System.out.println();
e.printStackTrace();
} catch (CryptoTokenException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (CryptoUnsupportedOperationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedCryptoSystemException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
这是我做的服务器端生成我的钥匙:
try {
keyPairGenerator = KeyPairGenerator.getInstance("RSA");
keyPairGenerator.initialize(1024);
keyFactory = KeyFactory.getInstance("RSA");
} catch (NoSuchAlgorithmException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
}
keyPair = keyPairGenerator.generateKeyPair();
publicKey = keyPair.getPublic();
privateKey = keyPair.getPrivate();
try {
publicKeySpec = keyFactory.getKeySpec(publicKey, RSAPublicKeySpec.class);
privateKeySpec = keyFactory.getKeySpec(privateKey, RSAPrivateKeySpec.class);
} catch (InvalidKeySpecException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
}
privateKeyModulus = privateKeySpec.getModulus().toString();
privateKeyExponent = privateKeySpec.getPrivateExponent().toString();
publicKeyModulus = publicKeySpec.getModulus().toString();
publicKeyExponent = publicKeySpec.getPublicExponent().toString();
任何想法?
编辑:我试图通过加密和解密那里的时候做服务器上一个简单的测试,当我尝试解密,我得到一个IllegalBlockSizeException
这些都是我encrytion和解密方法(服务器端):
public byte[] Decrypt(byte[] data)
{
try {
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.DECRYPT_MODE, privateKey);
byte[] cipherData = cipher.doFinal(data);
return cipherData;
} catch (NoSuchAlgorithmException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch (NoSuchPaddingException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(IllegalBlockSizeException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(InvalidKeyException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(BadPaddingException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
}
return null;
}
public byte[] Encrypt(byte[] data)
{
try {
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.ENCRYPT_MODE, publicKey);
byte[] cipherData = cipher.doFinal(data);
return cipherData;
} catch (NoSuchAlgorithmException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch (NoSuchPaddingException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(IllegalBlockSizeException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(InvalidKeyException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
} catch(BadPaddingException ex) {
Logger.getLogger(EncryptorDecryptor.class.getName()).log(Level.SEVERE, null, ex);
}
return null;
}
这是一个简单的测试,我试着:
userName = Base64.encode(encryptorDecryptor.Encrypt(userName.getBytes()));
password = Base64.encode(encryptorDecryptor.Encrypt(password.getBytes()));
userName = new String(encryptorDecryptor.Decrypt(Base64.decode(userName)));
password = new String(encryptorDecryptor.Decrypt(Base64.decode(password)));
我知道把它们保存为字符串不是最好的做法,但它只是一个服务器端隔离测试,其思想是我收到一个Base64编码的字节数组并将其转换为它所表示的正确字符串(如新编辑)。在服务器上的Java代码中,我没有问题使用这种方式的模数和指数来生成密钥,因此可以进行加密和解密,正如您在最终代码片段中所看到的(我对其进行了编辑)。如果我错了,那么正确的方式怎么样? – 8vius 2011-03-10 13:29:37
另外.getModulus()方法返回一个BigInteger而不是一个byte [] – 8vius 2011-03-10 14:13:22