0
我想创建一个Java列表视图,允许每个列表项目打开一个网址,但我似乎无法获得正确的代码。请有人告诉我哪里出了问题。无法使用Java获取列表项目正确的代码
package com.sasquatchapps.hydraquip10.bestofmonsterquest;
import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.Toast;
public class Season1Activity extends Activity{
private String episodes[] = {"America's Loch Ness Monster","Sasquatch Attack",
"Giant Squid Found","Birdzilla","Bigfoot","“Mutant K9","Lions in the Backyard","Gigantic Killer Fish","Swamp Beast","Russia's Killer Apemen","Unidentified Flying Creatures","The Real Hobbit",
"Giganto: The Real King Kong","American Werewolf"};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
ArrayAdapter<String> adapter = new
ArrayAdapter<>(this,
android.R.layout.simple_list_item_1, episodes);
setListAdapter(adapter);
}
@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
Toast.makeText(this, "Item clicked;" + episodes[position], Toast.LENGTH_SHORT).show();
if (position == 0) {
Intent intent = new Intent(android.content.Intent.ACTION_VIEW, Uri.parse("https://www.youtube.com/watch?v=o7-RdxrCFAg"));
startActivity(intent);
}
}
}
莫非你请详细说明你得到的错误。我想你可能会因为扩展Activity而得到编译时错误。不是ListActivity并尝试调用setListAdapter方法。 seContentView(int)也未被调用。 – Gobinath