如何排序基于从另一个数组在PHP中的数组？

Question

如何在PHP中基于另一个数组对数组进行排序？我个人的这个名单，其实他们是1300 +的人......我只在这里显示22人:)

人阵：

Array ( 
    [0] => Array ([name] => Kay [site] => ex [rate] => 10) 
    [1] => Array ([name] => Kat [site] => ih [rate] => 9.7) 
    [2] => Array ([name] => Kate [site] => tp [rate] => 9) 
    [3] => Array ([name] => rina [site] => tc [rate] => 9.8) 
    [4] => Array ([name] => Katay [site] => cfnm [rate] => 6.8) 
    [5] => Array ([name] => teriay [site] => sn [rate] => 7.6) 
    [6] => Array ([name] => Kaay [site] => tla [rate] => 9.7) 
    [7] => Array ([name] => na Kay [site] => bsc [rate] => 9.5) 
    [8] => Array ([name] => qwerty [site] => tdp [rate] => 9.5) 
    [9] => Array ([name] => Katey [site] => hd [rate] => 9.4) 
    [10] => Array ([name] => Kat Kay [site] => ss [rate] => 9.2) 
    [11] => Array ([name] => ina Kay [site] => pv [rate] => 9.43) 
    [12] => Array ([name] => ina [site] => rat [rate] => 9.32) 
    [13] => Array ([name] => atay [site] => trw [rate] => 9.32) 
    [14] => Array ([name] => erina [site] => tlm [rate] => 9.43) 
    [15] => Array ([name] => Ky [site] => ol [rate] => 8.34) 
    [16] => Array ([name] => ikay [site] => tb [rate] => 7.34) 
    [17] => Array ([name] => jay [site] => ta [rate] => 6.5) 
    [18] => Array ([name] => saday [site] => hfy [rate] => 4.6) 
    [19] => Array ([name] => tarans [site] => sd [rate] => 6.54) 
    [20] => Array ([name] => dastw [site] => si [rate] => 6.4) 
    [21] => Array ([name] => dyr say [site] => ex [rate] => 7.6) 
) 

并且存在另一个数组称为位点我想相应地显示它们，每个循环每个站点只有一个人，并且当站点数组到达结尾时，它将开始到顶部，直到人员列表完成读取。

由现场秩序阵列

Array ([0] => Array ([acronym] => exs [site_order] => 1) 
[1] => Array ([acronym] => ts [site_order] => 1) 
[2] => Array ([acronym] => ih [site_order] => 2) 
[3] => Array ([acronym] => tp [site_order] => 3) 
[4] => Array ([acronym] => tc [site_order] => 4) 
[5] => Array ([acronym] => cfnm [site_order] => 5) 
[6] => Array ([acronym] => sn [site_order] => 6) 
[7] => Array ([acronym] => tla [site_order] => 7) 
[8] => Array ([acronym] => bsc [site_order] => 8) 
[9] => Array ([acronym] => tdp [site_order] => 9) 
[10] => Array ([acronym] => lhd [site_order] => 10) 
[11] => Array ([acronym] => ss [site_order] => 11) 
[12] => Array ([acronym] => pov [site_order] => 12) 
[13] => Array ([acronym] => rat [site_order] => 13) 
[14] => Array ([acronym] => trw [site_order] => 14) 
[15] => Array ([acronym] => tgs [site_order] => 15) 
[16] => Array ([acronym] => tlm [site_order] => 16) 
[17] => Array ([acronym] => ol [site_order] => 17) 
[18] => Array ([acronym] => tb [site_order] => 18) 
[19] => Array ([acronym] => ta [site_order] => 19) 
[20] => Array ([acronym] => hfy [site_order] => 20) 
[21] => Array ([acronym] => sd [site_order] => 21) 
[22] => Array ([acronym] => si [site_order] => 22) 
[23] => Array ([acronym] => tse [site_order] => 23) 
[24] => Array ([acronym] => ih [site_order] => 24) 
) 

我也想通过率来显示它们。但我甚至不能显示正确的数据，因为当站点数组foreach完成后，它停止加载人。这是到目前为止我的代码...

$x = 0; 
$num = 0; 
foreach ($site as $item) { 
     foreach ($data as $person) 
     { 
      if($site[$num]['acronym'] == $persons['site'] && $x != 1) 
      { 
       echo 'name: '.$person['site'].'<br>'; 
       echo 'site: '.$person['name'].'<br>'; 
       echo '<br>'; 

       $x++; 
      } 
     } 
     $x = 0; 
    $num++; 
} 

我想要的输出，例如：

site: ex 
name: kay 
rate: 10 

site: tp 
name: kate 
rate: 9 

site: tc 
name: rina 
rate: 9.8 

site: ih 
name: kat 
rate: 9.7 

site: tla 
name: Kaay 
rate: 9.7 
. 
. 
. 
and so on 

注意，我希望有一个条件，即： 环路人员命令由现场下单和订单通过但每个站点循环只有一个人。

我知道这听起来有点复杂，但请帮助我。我在这里搜索了很多线程，与我有同样的问题，但没有运气。 ：'（

Answer 1

下面的代码是一个可能的解决方案：

$already_printed = Array(); 
$total_of_people = count($people); 
// while there is someone that was not printed yet 
while(count($already_printed) < $total_of_people){ 
    // iterate thought each site 
    foreach($sites as $site){ 
     // take each person and its position in the array 
     foreach ($people as $i => $person){ 
      // if this i-th person was not printed yet 
      // and is related to this $site 
      if (! isset($already_printed[$i]) 
       && $person['site'] == $site['acronym']){ 
       // print this person 
       echo 'site: '.$person['site'].'<br>'; 
       echo 'name: '.$person['name'].'<br>'; 
       echo '<br>'; 
       // mark this i-th person as printed 
       $already_printed[$i] = true; 
      } 

     } 
    } 
} 

的阵列already_printed用于知道谁已经打印以避免双重打印。当它的大小等于人的总数时，那么，我们印出每个人，所以，我们可以停止（这是外层循环所做的）。

Answer 2

的关键是，大型阵列组织成不强迫你通过它多次迭代超过所需的格式给这一个镜头：

$highest = array(); 

foreach ($data as $person) { 
    if (!array_key_exists($person['site'], $highest) || ($person['rate'] > $highest[$person['site']]['rate'])) { 
     $highest[$person['site']] = $person; 
    } 
} 

foreach ($site as $item) { 
    if (array_key_exists($item['acronym'], $highest)) { 
     echo "site: {$highest[$item['acronym']]['site']}<br />name:{$highest[$item['acronym']]['name']}<br />rate:{$highest[$item['acronym']]['rate']}"; 
    } 
} 

作为一个侧面说明，在不断变化的“女孩”到“人”良好的通话，所以这是不那么明显的创建率女性应用...

Answer 3

使用你的代码，我会做这样的事情：

foreach ($site as $item) { 
      $maxRate = 0; 
      $savePerson = array(); 
      foreach ($data as $person) 
      { 
       if($item['acronym'] == $girls['site'] && $person['site'] == $girls['site'] && $person['rate'] > $maxRate) 
       { 
        $maxRate = $person['rate']; 
        $savePerson = $person; 
       } 
      } 
      if(!empty($savePerson)){ 
        echo 'name: '.$savePerson['site'].'<br>'; 
        echo 'site: '.$savePerson['name'].'<br>'; 
        echo '<br>'; 
      } 
    } 

我并不确切地知道，如果你需要这个条件$人[“现场”] == $女孩[“现场”] ..如果你不能删除它。那只是我的感觉。

btw：你没有显示$女孩阵列，所以我只是假设只是以前计算。我假设的$ data是你正在谈论的$ persons数组。