迭代jquery对象

Question

我试图迭代并输出选项属性的值使用jquery each（）。我的代码似乎输出数组索引，而不是字符串值。为什么是这样？这是我jsfiddle

var allQuestions = [ 
    { 
    question: "Who is Prime Minister of the United Kingdom?", 
    choices: ["David Cameron", "Gordon Brown", "Winston Churchill", "Tony Blair"], 
    correctAnswer:0 
    }]; 


$(info[0].choices).each(function(value){ 
    $('#answers').append($('<li>').text(value)); 
}); 

Answer 1

试试这个

$(info[0].choices).each(function(value){ 
    $('#answers').append($('<li>').text(this)); 

Answer 2

你是路过的，而不是价值指数：

var allQuestions = [{ 
    question: "Who is Prime Minister of the United Kingdom?", 
    choices: ["David Cameron", "Gordon Brown", "Winston Churchill", "Tony Blair"], 
    correctAnswer:0 
}]; 


$(info[0].choices).each(function(index, value){ 
    $('#answers').append($('<li>').text(value)); 
}); 

下面是一个例子小提琴：http://jsfiddle.net/436Lcvc4/

Answer 3

的$.each回调需要两个参数index和value。添加value作为第二个参数并改为使用该参数。

Answer 4

你都弄得

$(selector).each() 

http://api.jquery.com/each/

与

$.each(array, callback) 

http://api.jquery.com/jquery.each/

你想使用第二种形式用于遍历数组。