2012-04-26 49 views
2

我在轨初学者,我有这个阵列的时候:如何将一个字符串数组转换为下拉列表框?

[ “08:30”, “09:00”, “09:30”, “10:00”,“10: 30“,”11:00“,”11:30“, ”12:00“,”12:30“,”13:00“,”13:30“,”14:00“,”14:30 “,”15:00“, ”15:30“,”16:00“,”16:30“,”17:00“,”17:30“,”18:00“,”18:30“ , “19:00”, “19:30”, “20:00”, “20:30”, “21:00”, “21:30”]

我怎么能转换成使用options_from_collection_for_select下拉菜单。我试着用

<%= select_tag "start_time", options_from_collection_for_select(@start_time,:id, :name) %>

但它返回"undefined method 'name' for "08:30":String"

回答

5

假设

@options = ["08:30", "09:00", "09:30", "10:00", "10:30", "11:00", "11:30", "12:00", "12:30", "13:00", "13:30", "14:00", "14:30", "15:00", "15:30", "16:00", "16:30", "17:00", "17:30", "18:00", "18:30", "19:00", "19:30", "20:00", "20:30", "21:00", "21:30"] 

代码将是

<%= select_tag "start_time", options_for_select(@options) %> 

参见options_for_select文档。

+0

感谢。有效! – 2012-04-26 10:21:51

0

您可以使用像下面

<%= f.select :time, options_for_select(MONTHS, @job.time) %> 

个月=>您的阵列

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