2
我试图编写库中的类的单元测试。建立lib和 测试是用CMake完成的。单元测试与CMake没有重复编译
├── CMakeLists.txt
├── src
│ ├── Bar.cpp
│ ├── CMakeLists.txt
│ └── Foo.cpp
└── test
├── BarTest.cpp
├── CMakeLists.txt
└── FooTest.cpp
src/CMakeLists.txt
只不过是add_library(Example Foo.cpp Bar.cpp)
。 而且因为我想打造的单元测试,而不构建库(即 如果我做出改变说Foo
我可以,而不必与Bar
的 互动已运行工作的单元测试。所以test/CMakeLists.txt
看起来像 这样的:
add_executable(FooTest FooTest.cpp ${CMAKE_SOURCE_DIR}/src/Foo.cpp)
add_test(bla::FooTest ${CMAKE_CURRENT_BINARY_DIR}/FooTest)
add_executable(BarTest BarTest.cpp ${CMAKE_SOURCE_DIR}/src/Bar.cpp)
add_test(bla::BarTest ${CMAKE_CURRENT_BINARY_DIR}/BarTest)
但是,这导致在每一个源文件是建立两次:
[ 11%] Building CXX object src/CMakeFiles/Example.dir/Foo.o
[ 22%] Building CXX object src/CMakeFiles/Example.dir/Bar.o
[ 33%] Linking CXX static library libExample.a
[ 33%] Built target Example
[ 44%] Building CXX object test/CMakeFiles/FooTest.dir/FooTest.o
[ 55%] Building CXX object test/CMakeFiles/FooTest.dir/__/src/Foo.o
[ 66%] Linking CXX executable FooTest
[ 66%] Built target FooTest
[ 77%] Building CXX object test/CMakeFiles/BarTest.dir/BarTest.o
[ 88%] Building CXX object test/CMakeFiles/BarTest.dir/__/src/Bar.o
[100%] Linking CXX executable BarTest
[100%] Built target BarTest
是否有可能避免这也就是说,如果我有建src/Foo.cpp
b对于 单元测试之前,不要再为一个库建立它?所有的标志都是一样的。