Android的凌空不能在单独的类中获得价值

Question

public class VolleyStringRequest { 
    String url; 
    String body; 
    String value; 
    public VolleyStringRequest(String url, String body){ 
     this.url = url; 
     this.body = body; 
     value= ""; 
    } 
    public StringRequest createStringRequest(){ 
     StringRequest stringRequest = new StringRequest(Request.Method.POST, url, 
       new Response.Listener<String>() { 
        @Override 
        public void onResponse(String response) { 
         // Do something with the response 
         Log.e("Response", response); 
         try{ 
          JSONObject o = new JSONObject(response); 
          JSONArray values=o.getJSONArray("response"); 
          value += values.toString(); 
         } catch (JSONException ex){} 

        } 
       }, 
       new Response.ErrorListener() { 
        @Override 
        public void onErrorResponse(VolleyError error) { 
         // Handle error 
        } 
       }) { 
      @Override 
      public byte[] getBody() throws AuthFailureError { 
       return body.getBytes(); 
      }; 
      @Override 
      public String getBodyContentType() { 
       return "application/json"; 
      } 
     }; 
     return stringRequest; 
    } 

    public String getValue() { 
     return value; 
    } 
} 

我在一个单独的类写了这个代码，以防止重复的代码，但是当我运行这个像这样的片段中：

RequestQueue rq = Volley.newRequestQueue(getActivity().getApplicationContext()); 
     String url= "http://grwn.ddns.net:1337/results"; 
     final String body = "{\"id\":1}"; 
     VolleyStringRequest volleyStringRequest = new VolleyStringRequest(url, body); 
     rq.add(volleyStringRequest.createStringRequest()); 
     volleyStringRequest.getValue(); 

，并调用getValue()方法。此方法始终为空：“”。有谁知道我可以如何提高我的课程，这样的代码将工作？这个问题并不是因为错误的链接或错误的请求。我可以登录响应，并且不工作（ofcourse内VolleyStringRequest）

Answer 1

您运行：

VolleyStringRequest volleyStringRequest = new VolleyStringRequest(url, body); 
rq.add(volleyStringRequest.createStringRequest()); 
volleyStringRequest.getValue(); 

但要记住createStringRequest是异步方法和value一定延迟后酸当量人口里面public void onResponse(String response)

所以，当你调用volleyStringRequest.getValue();你空字符串

为了使它工作，你可以写一些接口：

public interface RequestHandlerInterface(){ 
    void onResponse(String resp); 
    } 

并将它传递给VolleyStringRequest构造：

RequestHandlerInterface rh = this; //Your main class should implement this method 
    RequestQueue rq = Volley.newRequestQueue(getActivity().getApplicationContext()); 
    String url= "http://grwn.ddns.net:1337/results"; 
    final String body = "{\"id\":1}"; 
    VolleyStringRequest volleyStringRequest = new VolleyStringRequest(url, body, rh); 
    rq.add(volleyStringRequest.createStringRequest()); 

接下来，更改您的VolleyStringRequest：

public class VolleyStringRequest { 
    String url; 
    String body; 
    String value; 
    public VolleyStringRequest(String url, String body, RequestHandlerInterface rh){ 
     this.url = url; 
     this.body = body; 
     this.rh = rh; 
     value= ""; 
    } 
    //... 
} 

而且一旦你得到了POST响应，调用回调为：

@Override 
public void onResponse(String response) { 
    // Do something with the response 
     Log.e("Response", response); 
     try{ 
      JSONObject o = new JSONObject(response); 
      JSONArray values=o.getJSONArray("response"); 
      value += values.toString(); 
      if(this.rh != null){ 
      this.rh.onResponse(value); 
      } 
      } catch (JSONException ex){} 
} 

所以在底线，而不是调用volleyStringRequest.getValue();

您有：

@Override 
void onResponse(String resp){ 
    // here you go 
} 

，这将是当你得到POST回应时调用